Circular Motion A 1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point "A", and the total mechanical energy of the bead is assumed to be constant as it moves around the circle. Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to point "B" each cycle. 10 m/s 2m 1 Note: vector directions should be given as the "standard" angle with 0<0 < 360 degrees Previous 30° Calculate the direction of the velocity of the bead at point "B". Enter the standard angle in degrees.

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Chapter1: Units, Trigonometry. And Vectors
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Circular Motion
A 1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no
friction between the bead and the circular track. The bead has a speed of 10 m/s
when at the top of the circle at point "A", and the total mechanical energy of the
bead is assumed to be constant as it moves around the circle.
Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to
point "B" each cycle.
10 m/s
2 m
Previous
A
30°
Note: vector directions should be given as the "standard" angle with
0 ≤0 < 360 degrees
Calculate the direction of the velocity of the bead at point "B". Enter the standard
angle in degrees.
Transcribed Image Text:Circular Motion A 1 Kg bead is confined to move on a vertical circle of radius 2 meters. There is no friction between the bead and the circular track. The bead has a speed of 10 m/s when at the top of the circle at point "A", and the total mechanical energy of the bead is assumed to be constant as it moves around the circle. Assume it takes the bead 0.62 seconds to go counter-clockwise from point "A" to point "B" each cycle. 10 m/s 2 m Previous A 30° Note: vector directions should be given as the "standard" angle with 0 ≤0 < 360 degrees Calculate the direction of the velocity of the bead at point "B". Enter the standard angle in degrees.
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