A block of mass m = 1 kg is sliding on a horizontal surface with initial velocity vo = 2 m/s. The block is brought to a stop by kinetic friction in a distance of 4 m. What is the work done by the force of friction acting on the block? -2 J -8 J O 2 J 8J -0.5 J 0.5 J

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Chapter1: Units, Trigonometry. And Vectors
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A block of mass m = 1 kg is sliding on a horizontal surface with initial velocity vo = 2 m/s. The block
is brought to a stop by kinetic friction in a distance of 4 m. What is the work done by the force of
friction acting on the block?
-2 J
-8 J
2J
8 J
-0.5 J
0.5 J
Transcribed Image Text:A block of mass m = 1 kg is sliding on a horizontal surface with initial velocity vo = 2 m/s. The block is brought to a stop by kinetic friction in a distance of 4 m. What is the work done by the force of friction acting on the block? -2 J -8 J 2J 8 J -0.5 J 0.5 J
Expert Solution
Step 1

Solution:

Given:

m = mass of block = 1 kg

v0 = speed of block = 2ms

s = distance in which block is brought to stop by kinetic friction =   4 m 

U3 = work done by the force of friction on the block = ?

We will find the answer using the standard formula. 

 

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