The only force acting on an object is F 10N in the +x direction. The object travels from = (-4î - 6ĵ) m to r₂ = (+41 + 6ĵ) m. What is the work done by this force?

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Chapter1: Units, Trigonometry. And Vectors
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Problem 5:
The only force acting on an object is F =
10N in the +x direction. The object travels
from ₁ = (-4î - 6ĵ) m to 2 = (+4î +
6ĵ) m. What is the work done by this force?
Lenovo
F1
F2
A+
#
F3
F4
F5
0/
F6
F7
Transcribed Image Text:Problem 5: The only force acting on an object is F = 10N in the +x direction. The object travels from ₁ = (-4î - 6ĵ) m to 2 = (+4î + 6ĵ) m. What is the work done by this force? Lenovo F1 F2 A+ # F3 F4 F5 0/ F6 F7
Expert Solution
Step 1

Given

Force acting on the object is F=10i^ N  (the force is acting along +x direction)

Initial position of the object is r1=(-4i^-6j^)

Final position of the object is r2=(+4i^+6j^)

 

We have to find the work done by this force.

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