CI CH3-CH=CH-CH3 CH3-CH2-C-CH3 HCECH CH3-CH2-CH-CH3 Br

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How should each of the following contents be prepared? Use the specified starting material and any other reagents

### Transcription and Explanation of Chemical Reactions

#### Reaction 1: Addition of Chlorine to an Alkene

**Reactant:**
- \( \text{CH}_3\text{CH}=\text{CHCH}_3 \)

**Product:**
- \( \text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3 \)

**Description:**
This reaction involves the addition of chlorine (Cl\(_2\)) across a double bond in an alkene. The molecule \(\text{CH}_3\text{CH}=\text{CHCH}_3\), which contains a carbon-carbon double bond, reacts with chlorine to form \(\text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3\), a dibromoalkane. This process results in the saturation of the double bond, converting it into a single bond and adding two chlorine atoms to the carbon atoms that were previously involved in the double bond.

#### Reaction 2: Addition of Bromine to an Alkyne

**Reactant:**
- \(\text{HC}\equiv\text{CH}\)

**Product:**
- \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\)

**Description:**
This reaction illustrates the addition of bromine (Br\(_2\)) to an alkyne. The starting molecule \(\text{HC}\equiv\text{CH}\) involves a carbon-carbon triple bond. Upon reaction with bromine, the alkyne is converted to a bromoalkane \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\), where the triple bond is first broken down to a double bond and then further reacted to form a single bond, with one bromine atom added to each carbon atom.

### Explanation of Diagrams

**Diagram 1: Chlorination Process**
- Shows the transformation of a simple alkene into a dibromoalkane via halogen addition, highlighting the saturation of the double bond and addition of halogen atoms.

**Diagram 2: Bromination Process**
- Illustrates the transformation of an alkyne into a bromoalkane. Initially represented is the breaking of the triple bond and subsequent addition of bromine atoms, leading to its conversion into a
Transcribed Image Text:### Transcription and Explanation of Chemical Reactions #### Reaction 1: Addition of Chlorine to an Alkene **Reactant:** - \( \text{CH}_3\text{CH}=\text{CHCH}_3 \) **Product:** - \( \text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3 \) **Description:** This reaction involves the addition of chlorine (Cl\(_2\)) across a double bond in an alkene. The molecule \(\text{CH}_3\text{CH}=\text{CHCH}_3\), which contains a carbon-carbon double bond, reacts with chlorine to form \(\text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3\), a dibromoalkane. This process results in the saturation of the double bond, converting it into a single bond and adding two chlorine atoms to the carbon atoms that were previously involved in the double bond. #### Reaction 2: Addition of Bromine to an Alkyne **Reactant:** - \(\text{HC}\equiv\text{CH}\) **Product:** - \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\) **Description:** This reaction illustrates the addition of bromine (Br\(_2\)) to an alkyne. The starting molecule \(\text{HC}\equiv\text{CH}\) involves a carbon-carbon triple bond. Upon reaction with bromine, the alkyne is converted to a bromoalkane \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\), where the triple bond is first broken down to a double bond and then further reacted to form a single bond, with one bromine atom added to each carbon atom. ### Explanation of Diagrams **Diagram 1: Chlorination Process** - Shows the transformation of a simple alkene into a dibromoalkane via halogen addition, highlighting the saturation of the double bond and addition of halogen atoms. **Diagram 2: Bromination Process** - Illustrates the transformation of an alkyne into a bromoalkane. Initially represented is the breaking of the triple bond and subsequent addition of bromine atoms, leading to its conversion into a
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