Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How should each of the following contents be prepared? Use the specified starting material and any other reagents
![### Transcription and Explanation of Chemical Reactions
#### Reaction 1: Addition of Chlorine to an Alkene
**Reactant:**
- \( \text{CH}_3\text{CH}=\text{CHCH}_3 \)
**Product:**
- \( \text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3 \)
**Description:**
This reaction involves the addition of chlorine (Cl\(_2\)) across a double bond in an alkene. The molecule \(\text{CH}_3\text{CH}=\text{CHCH}_3\), which contains a carbon-carbon double bond, reacts with chlorine to form \(\text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3\), a dibromoalkane. This process results in the saturation of the double bond, converting it into a single bond and adding two chlorine atoms to the carbon atoms that were previously involved in the double bond.
#### Reaction 2: Addition of Bromine to an Alkyne
**Reactant:**
- \(\text{HC}\equiv\text{CH}\)
**Product:**
- \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\)
**Description:**
This reaction illustrates the addition of bromine (Br\(_2\)) to an alkyne. The starting molecule \(\text{HC}\equiv\text{CH}\) involves a carbon-carbon triple bond. Upon reaction with bromine, the alkyne is converted to a bromoalkane \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\), where the triple bond is first broken down to a double bond and then further reacted to form a single bond, with one bromine atom added to each carbon atom.
### Explanation of Diagrams
**Diagram 1: Chlorination Process**
- Shows the transformation of a simple alkene into a dibromoalkane via halogen addition, highlighting the saturation of the double bond and addition of halogen atoms.
**Diagram 2: Bromination Process**
- Illustrates the transformation of an alkyne into a bromoalkane. Initially represented is the breaking of the triple bond and subsequent addition of bromine atoms, leading to its conversion into a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9236b64-b4cd-48d9-84e5-ba64ef39dc54%2F1be35003-b37b-4846-8e3c-9b521e39bbbd%2F9bka68b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Transcription and Explanation of Chemical Reactions
#### Reaction 1: Addition of Chlorine to an Alkene
**Reactant:**
- \( \text{CH}_3\text{CH}=\text{CHCH}_3 \)
**Product:**
- \( \text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3 \)
**Description:**
This reaction involves the addition of chlorine (Cl\(_2\)) across a double bond in an alkene. The molecule \(\text{CH}_3\text{CH}=\text{CHCH}_3\), which contains a carbon-carbon double bond, reacts with chlorine to form \(\text{CH}_3\text{CH}_2\text{C(Cl)ClCH}_3\), a dibromoalkane. This process results in the saturation of the double bond, converting it into a single bond and adding two chlorine atoms to the carbon atoms that were previously involved in the double bond.
#### Reaction 2: Addition of Bromine to an Alkyne
**Reactant:**
- \(\text{HC}\equiv\text{CH}\)
**Product:**
- \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\)
**Description:**
This reaction illustrates the addition of bromine (Br\(_2\)) to an alkyne. The starting molecule \(\text{HC}\equiv\text{CH}\) involves a carbon-carbon triple bond. Upon reaction with bromine, the alkyne is converted to a bromoalkane \(\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3\), where the triple bond is first broken down to a double bond and then further reacted to form a single bond, with one bromine atom added to each carbon atom.
### Explanation of Diagrams
**Diagram 1: Chlorination Process**
- Shows the transformation of a simple alkene into a dibromoalkane via halogen addition, highlighting the saturation of the double bond and addition of halogen atoms.
**Diagram 2: Bromination Process**
- Illustrates the transformation of an alkyne into a bromoalkane. Initially represented is the breaking of the triple bond and subsequent addition of bromine atoms, leading to its conversion into a
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