Choose the correct major product for the following reaction: N Ent H N 1. LIAIH4 (XS) 2. H₂O 3. O OH Orton a [H*] NaBH3CN HO Z-I N Cax N

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**Title: Identifying the Major Product in a Multi-Step Organic Reaction**

**Question:**
Choose the correct major product for the following reaction:

**Reaction Details:**
- Starting Material: A six-membered lactam (cyclic amide) compound with an N-methyl group.
- Reaction Steps:
  1. Lithium aluminum hydride (LiAlH₄) in excess (xs)
  2. Water (H₂O)
  3. Under acidic conditions ([H⁺]), the intermediate is reacted with acetone and sodium cyanoborohydride (NaBH₃CN).

**Potential Products:**

- **A:** A cyclic amide with an additional N-isopropyl group.
- **B:** A cyclic alcohol with a tertiary alcohol group and an N-methyl group.
- **C:** A linear compound with a 1,5-diol structure and an N-isopropyl group.
- **D:** A cyclic amine with an N-isopropyl group.

**Product Options:**
- ○ A
- ○ B
- ○ C
- ○ D

**Explanation of Reaction Steps:**

1. **Reduction with LiAlH₄:** Converts the lactam into a cyclic amine. This step involves the reduction of the carbonyl group in the lactam to an amine.

2. **Protonation with Water:** Quenches the excess hydride, providing the uncharged, reduced amine.

3. **Reductive Amination:** The amine then undergoes reductive amination with acetone under acidic conditions using NaBH₃CN, adding an isopropyl group to the nitrogen.

The task is to determine which of the given options corresponds to the description of the product after these reactions. The reaction likely produces a cyclic amine with an N-substituted isopropyl group, given the use of acetone and NaBH₃CN in reductive amination.
Transcribed Image Text:**Title: Identifying the Major Product in a Multi-Step Organic Reaction** **Question:** Choose the correct major product for the following reaction: **Reaction Details:** - Starting Material: A six-membered lactam (cyclic amide) compound with an N-methyl group. - Reaction Steps: 1. Lithium aluminum hydride (LiAlH₄) in excess (xs) 2. Water (H₂O) 3. Under acidic conditions ([H⁺]), the intermediate is reacted with acetone and sodium cyanoborohydride (NaBH₃CN). **Potential Products:** - **A:** A cyclic amide with an additional N-isopropyl group. - **B:** A cyclic alcohol with a tertiary alcohol group and an N-methyl group. - **C:** A linear compound with a 1,5-diol structure and an N-isopropyl group. - **D:** A cyclic amine with an N-isopropyl group. **Product Options:** - ○ A - ○ B - ○ C - ○ D **Explanation of Reaction Steps:** 1. **Reduction with LiAlH₄:** Converts the lactam into a cyclic amine. This step involves the reduction of the carbonyl group in the lactam to an amine. 2. **Protonation with Water:** Quenches the excess hydride, providing the uncharged, reduced amine. 3. **Reductive Amination:** The amine then undergoes reductive amination with acetone under acidic conditions using NaBH₃CN, adding an isopropyl group to the nitrogen. The task is to determine which of the given options corresponds to the description of the product after these reactions. The reaction likely produces a cyclic amine with an N-substituted isopropyl group, given the use of acetone and NaBH₃CN in reductive amination.
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