**Reaction Product Selection****Problem Statement:**Choose the correct product for the following reaction.**Reaction Sequence:**- **Starting Material:** Alkyl bromide compound- **Reagents and Conditions:** 1. Sodium azide (NaN₃) 2. Excess lithium aluminum hydride (LiAlH₄, xs) 3. Water (H₂O)**Product Options:**- **A:** Alkyl amine with the amine group on the terminal carbon- **B:** Alkyl amine with the amine group on the secondary carbon- **C:** Hydrocarbon with no functional groups- **D:** Alkyl azide with the azide group on the terminal carbon- **E:** Starting alkyl bromide compound**Choose One:**- A- B- C- D- E**Explanation:**The reaction in question involves an alkyl bromide undergoing substitution with sodium azide to form an alkyl azide. This intermediate then reacts with excess LiAlH₄, reducing the azide to an amine. Water is used in the final step to complete the reaction, resulting in an amine product. The correct product will reflect these transformations.

In the first step of the reaction the alkyl halide reacts with the sodium azize to form an alkyl…

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Chemistry

Choose the correct product for the following reaction. xBr 1. NaN3 2. LIAIH4 (XS) 3. H₂O

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

Question

**Reaction Product Selection**

**Problem Statement:**

Choose the correct product for the following reaction.

**Reaction Sequence:**

- **Starting Material:** Alkyl bromide compound
- **Reagents and Conditions:**
1. Sodium azide (NaN₃)
2. Excess lithium aluminum hydride (LiAlH₄, xs)
3. Water (H₂O)

**Product Options:**

- **A:** Alkyl amine with the amine group on the terminal carbon
- **B:** Alkyl amine with the amine group on the secondary carbon
- **C:** Hydrocarbon with no functional groups
- **D:** Alkyl azide with the azide group on the terminal carbon
- **E:** Starting alkyl bromide compound

**Choose One:**

- A
- B
- C
- D
- E

**Explanation:**

The reaction in question involves an alkyl bromide undergoing substitution with sodium azide to form an alkyl azide. This intermediate then reacts with excess LiAlH₄, reducing the azide to an amine. Water is used in the final step to complete the reaction, resulting in an amine product. The correct product will reflect these transformations.

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Step 1: Conversion of alkyl bromide into amine

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