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Choose one of the expressions below and evaluate when n = 7: 2 n²-9 2(4-3) or (n+3) n- - 3 8-3.2

Choose one of the expressions below and evaluate when n = 7: 2 n²-9 2(4-3) or (n+3) n- - 3 8-3.2

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Algebraic Expression Evaluation **Instructions:** Choose one of the expressions below and evaluate it for \( n = 7 \): 1. \[\frac{n^2 - 9}{2(4 - 3)}\] 2. \[\left( n + 3 \right) \cdot \frac{n - 3}{8 - 3 \cdot 2}\] ### Explanation: - **Expression 1:** \[\frac{n^2 - 9}{2(4 - 3)}\] - This expression involves squaring the variable \( n \), subtracting 9, and dividing by the product of 2 and the difference of 4 and 3. - **Expression 2:** \[\left( n + 3 \right) \cdot \frac{n - 3}{8 - 3 \cdot 2}\] - This expression is a product of two parts. The first part is \( n + 3 \), while the second part is a fraction with the numerator \( n - 3 \) and the denominator being the result of 8 minus the product of 3 and 2. ### Evaluation for \( n = 7 \): - **For Expression 1:** Substitute \( n = 7 \): \[\frac{7^2 - 9}{2(4 - 3)} = \frac{49 - 9}{2 \cdot 1} = \frac{40}{2} = 20\] - **For Expression 2:** Substitute \( n = 7 \): \[\left( 7 + 3 \right) \cdot \frac{7 - 3}{8 - 3 \cdot 2} = 10 \cdot \frac{4}{8 - 6} = 10 \cdot \frac{4}{2} = 10 \cdot 2 = 20\]
Transcribed Image Text:### Algebraic Expression Evaluation **Instructions:** Choose one of the expressions below and evaluate it for \( n = 7 \): 1. \[\frac{n^2 - 9}{2(4 - 3)}\] 2. \[\left( n + 3 \right) \cdot \frac{n - 3}{8 - 3 \cdot 2}\] ### Explanation: - **Expression 1:** \[\frac{n^2 - 9}{2(4 - 3)}\] - This expression involves squaring the variable \( n \), subtracting 9, and dividing by the product of 2 and the difference of 4 and 3. - **Expression 2:** \[\left( n + 3 \right) \cdot \frac{n - 3}{8 - 3 \cdot 2}\] - This expression is a product of two parts. The first part is \( n + 3 \), while the second part is a fraction with the numerator \( n - 3 \) and the denominator being the result of 8 minus the product of 3 and 2. ### Evaluation for \( n = 7 \): - **For Expression 1:** Substitute \( n = 7 \): \[\frac{7^2 - 9}{2(4 - 3)} = \frac{49 - 9}{2 \cdot 1} = \frac{40}{2} = 20\] - **For Expression 2:** Substitute \( n = 7 \): \[\left( 7 + 3 \right) \cdot \frac{7 - 3}{8 - 3 \cdot 2} = 10 \cdot \frac{4}{8 - 6} = 10 \cdot \frac{4}{2} = 10 \cdot 2 = 20\]
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