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100M Laura was asked to expand the expression log in terms of log M, log N, and constants. Laura's work/explanation: First I have to use the 2nd Log Law to turn the log of a quotient into a difference of logs: 100M log = log(100M) – log N² Now I have to use the 1st Log Law to turn the log of a product into a sum of logs: log 100 + log M - log N2 And finally I have to use the 3rd Log Law to turn the argument's exponent into the log's coefficient: log 100 + log M- 2 log N

100M Laura was asked to expand the expression log in terms of log M, log N, and constants. Laura's work/explanation: First I have to use the 2nd Log Law to turn the log of a quotient into a difference of logs: 100M log = log(100M) – log N² Now I have to use the 1st Log Law to turn the log of a product into a sum of logs: log 100 + log M - log N2 And finally I have to use the 3rd Log Law to turn the argument's exponent into the log's coefficient: log 100 + log M- 2 log N

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter11: Exponential And Logarithmic Functions
Section11.CR: Review Problem Set
Problem 33CR
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100M Laura was asked to expand the expression log in terms of log M, log N, and constants. Laura's work/explanation: First I have to use the 2nd Log Law to turn the log of a quotient into a difference of logs: 100M log = log(100M) – log N2 Now I have to use the 1st Log Law to turn the log of a product into a sum of logs: log 100 + log M – log N? And finally I have to use the 3rd Log Law to turn the argument's exponent into the log's coefficient: log 100 + log M – 2 log N
Transcribed Image Text:100M Laura was asked to expand the expression log in terms of log M, log N, and constants. Laura's work/explanation: First I have to use the 2nd Log Law to turn the log of a quotient into a difference of logs: 100M log = log(100M) – log N2 Now I have to use the 1st Log Law to turn the log of a product into a sum of logs: log 100 + log M – log N? And finally I have to use the 3rd Log Law to turn the argument's exponent into the log's coefficient: log 100 + log M – 2 log N
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