Chi-Square TestsValueHPdfAsymptoticSignificance(2-sided)Pearson Chi-Square46.157a8000Likelihood48.412 8000RatioLinear-by-10.2711001LinearAssociationN of ValidCases1306a. 2 cells (11.1%) have expected count lessthan 5. The minimum expected count is 2.26.The above table looks at the association between death from gun violence and education status. Based on the results, which ofthe following statements is correct:There is a significant association between the two variablesThere is not a significant association between the two variablesThe chi-square variable cannot be interpretedHigh education is associated with more gun deaths

The Pearson Chi-Square is reported as 46.157 with a p-value of < .001. Since p < 0.05, we may…

Answered: Chi-Square Tests Value HP df Asymptotic…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A study was conducted to examine how fear of public speaking varies across year of tertiary education (1st, 2nd or 3rd). Subjects were interviewed at the end of each of year of their tertiary education for fear of public speaking (measured on a 10 point metric scale). Which of the following would be an appropriate statistical test to conduct, which addresses these hypotheses? Group of answer choices: Factorial ANOVA Mixed ANOVA Multiple Regression Within Subjects ANOVA Single Factor ANOVA
Job satisfaction as a function of a work schedule was investigated in different factories. In the first factory, the employees are on fixed shift system while in the second factor, the workers have rotating shift system. Using the data in the table below, determine if there is a significant difference in job satisfaction between the two groups of workers. Use 0.01 level of significance. Shift Schedule Mean Standard Deviation Sample size Fixed 7.43 2.42 23 Rotating 6.18 2.15 29
A homeless shelter program wants to know if receipt of job training program (yes, no) is related to program satisfaction (measured on a multi-item, Likert scale ). What type of statistical test should be used? Group of answer choices Independent t-test Dependent t-test ANOVA Correlation Analysis Chi Square
What is the test statistic?(3 decimal places) What is the critical value(s)?(3 decimal places) Reject or don’t reject?
A sample of 33 lights in Austin gives an average of 46 cars/min while the city SD=3.4 A sample of 34 Dallas lights give a mean of 44 cars/mim with the city SD=1.4 At the 91% level, do the towns differ? 1. Is the test (A-Left Tailed, B-Right Tailed, C-2-Tailed) (separate with comma if there are 2) 2. Critical Value 3. Test statistic 4. 3-decimal p-Value
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
In this problem, we use your critical values table to explore the significance ofr based on different sample sizes. Critical Values for Correlation Coefficient r a = 0.05 =0.01 „A=0.05 a = 0.01 a = 0.05 a = 0.01 3. 1.00 1.00 13 0.53 0.68 23 0.41 0.53 4. 0.95 0.99 14 0.53 0.66 24 0.40 0.52 0.88 0.96 15 0.51 0.64 25 0.40 0.51 6. 0.81 0.92 16 0.50 0.61 26 0.39 0.50 0.75 0.87 17 0.48 0.61 27 0.38 0.49 8. 0.71 0.83 18 0.47 0.59 28 0.37 0.48 9. 0.67 0.80 19 0.46 0.58 29 0.37 0.47 10 0.63 0.76 20 0.44 0.56 30 0.36 0.46 11 0.60 0.73 21 0.43 0.55 12 0.58 0.71 22 0.42 0.54
A random sample of n1 = 49 measurements from a population with population standard deviation ?1 = 3 had a sample mean of x1 = 10. An independent random sample of n2 = 64 measurements from a second population with population standard deviation ?2 = 4 had a sample mean of x2 = 12. Test the claim that the population means are different. Use level of significance 0.01. (a) Check Requirements: What distribution does the sample test statistic follow? Explain. The Student's t. We assume that both population distributions are approximately normal with known standard deviations.The standard normal. We assume that both population distributions are approximately normal with known standard deviations. The Student's t. We assume that both population distributions are approximately normal with unknown standard deviations.The standard normal. We assume that both population distributions are approximately normal with unknown standard deviations. (b) State the hypotheses. H0: ?1 = ?2;…
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
When comparing more than two treatment means, why should you use an analysis of variance instead of using multiple t tests? Question 31 options: Using multiple t tests increases the risk of a Type II error The analysis of variance is more likely to detect a treatment effect Using multiple t tests increases the risk of a Type I error There is no advantage to using an analysis of variance instead of multiple t tests
what is the expected frequency for this data? n total =13

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