Chi-Square Tests Value HP df Asymptotic Significance (2-sided) Pearson Chi- Square 46.157a 8 000 Likelihood 48.412 8 000 Ratio Linear-by- 10.271 1 001 Linear Association N of Valid Cases 1306 a. 2 cells (11.1%) have expected count less than 5. The minimum expected count is 2.26. The above table looks at the association between death from gun violence and education status. Based on the results, which of the following statements is correct: There is a significant association between the two variables There is not a significant association between the two variables The chi-square variable cannot be interpreted High education is associated with more gun deaths

Which combination would lead you to Fail to Reject H0? Correlation:           robt = 0.68      rcrit = 0.64   ANOVA:                  Fobt = 3.61      Fcrit = 2.55 Chi-Square GOF:   χ2obt = 3.24    χ2crit = 4.25 2-tailed t-test:       tobt = 2.36      tcrit = 1.89

Which combination would lead you to Fail to Reject H0? ANOVA:                  Fobt = 3.61      Fcrit = 2.55 2-tailed t-test:       tobt = 2.36      tcrit = 1.89 Correlation:           robt = 0.68      rcrit = 0.64 Chi-Square GOF:   χ2obt = 3.24    χ2crit = 4.25

widely used as dielectrics and coolants in electrical systems in the past. They were found to be a major environmental contaminant in the 1960s. In a study, the mean PCB content at each of thirteen sites was reported for the years 1982 and 1996 (from “The ratio of DDE to PCB concentrations in Great Lakes herring gull eggs and its use in interpreting contaminants data”, Journal of Great Lakes Research 24 (1): 12-31, 1998). The data are below.Site:12345678910111213198261.4864.4745.5059.7058.8175.9671.5738.0630.5139.7029.7866.8963.93199613.9918.2611.2810.0221.0017.3628.207.3012.809.4112.6316.8322.74(a) Which test would be more appropriate in this case: a t-test for the difference between two population means, or a paired t-test? Why?(b) Do the data provide sufficient evidence to support the claim that the mean PCB level has decreased in the region? Be sure to check all assumptions, write the null and alternative hypotheses, calculate the appropriate test statistic, calculate the p-value,…

The lowest level of significance to reject the null hypothesis of no linear association between blood pressure and age is: OA: 0.003 OB: 0.05 OC: 0.0002 OD: 0.0001 OE: 0.04

Which of the following can cause OLS estimators to be biased?(i) Heteroskedasticity.(ii) Omitting an important variable.(iii) A sample correlation coefficient of .95 between two independent variables both included in the model.

To investigate if online tutoring is as effective (measured by passing rate) as tutoring in person, we collected random samples of students using each of the tutoring method exclusively and performed two statistical analysis (Chi square and correlation). In the outputs, tutor=1 means online, tutor=0 in person, pass =1 means passed a course while 0 means failed. Choose the correct method and report your findings.            Output1           Pearson Correlation Coefficients,  Prob > |r| under H0: Rho=0                                                tutoring          pass                                tutoring       1.00000       0.47579                                                                      0.0642                              pass           0.47579       1.00000                                                       0.0642 Output2                                                                         pass      tutor                                 Frequency‚…

You are shown ZJKL below whose measure is 90°. Draw an angle bisector of ZJKL by clicking a dragging a ray out from the vertex at K. Click and drag to draw a ray from the yellow dot. To redraw, click and drag from the yellow dot again. mZJKL = 90° mZJKM = 45° m/LKM = 45° L C

Sulfur dioxide (SO2) pollution is a known cause for corrosion of exposed steel.  To document this effect in actual conditions, steel weight loss (gm/m3/yr) was measured at 36 locations in a large city, along with the rate at which SO2 was deposited (mg/m2/day).  Obtain an estimate of the correlation between steel loss and sulfur dioxide deposition rate and interpret it. Give a 95% confidence interval for its value.  SO2 Loss 22.6 580 26.1 563 19.1 339 17.2 346 25 623 16.8 420 42.7 951 30.4 794 17.9 461 30.4 757 27.8 573 27.8 656 33 990 14.2 551 37.4 856 16.2 443 27.7 802 22.7 657 21 495 15.8 496 13.7 353 24.7 724 23.7 602 30.7 639 33.5 813 30.2 770 20.1 556 22.8 557 39.9 1001 15.5 432 40.4 940 27.9 687 39.4 919 25.1 590 28.6 640 29.7 702

(d) Estimate the total charge for an individual who stays 11 days in the hospital. (3 decimals)(e) Suppose we compare two patients and one stays 3 days longer in the hospital than the other.What is the expected difference in total charges between these patients?Suppose the sample correlation coefficient is ? = 0.88. Is there evidence of a significantcorrelation between the length of stay and the total charge? Run the appropriate test at ? = 0.05.