### Gas Phase Decomposition of Sulfuryl Chloride **Decomposition Reaction:** \[ \text{SO}_2\text{Cl}_2 \rightarrow \text{SO}_2 + \text{Cl}_2 \] **Conditions:** - Temperature: 600 K **Experimental Data:** The following table represents the concentration of sulfuryl chloride \((\text{SO}_2\text{Cl}_2)\) over different time intervals: | \([\text{SO}_2\text{Cl}_2]\), M | 3.55 × 10\(^-3\) | 2.35 × 10\(^-3\) | 1.55 × 10\(^-3\) | 1.02 × 10\(^-3\) | |--------------------------------|------------------|------------------|------------------|------------------| | **Time, min** | 0 | 148 | 296 | 444 | **Calculation Task:** Determine the average rate of disappearance of \(\text{SO}_2\text{Cl}_2\) using the concentration data from \( t = 0 \, \text{min} \) to \( t = 148 \, \text{min} \). **Required Answer:** The average rate of disappearance of \(\text{SO}_2\text{Cl}_2\) over the given time period is as follows: \[ \text{Rate} = \frac{\Delta [\text{SO}_2\text{Cl}_2]}{\Delta t} \] Where: - \(\Delta [\text{SO}_2\text{Cl}_2] = (\text{Final concentration} - \text{Initial concentration})\) - \(\Delta t = (\text{Final time} - \text{Initial time})\) Substitute the values: \[ \Delta [\text{SO}_2\text{Cl}_2] = 2.35 \times 10^{-3} \, \text{M} - 3.55 \times 10^{-3} \, \text{M} = -1.20 \times 10^{-3} \, \text{M} \] \[ \Delta t = 148 \, \text{min} - 0 \, \text{min} = 148

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### Gas Phase Decomposition of Sulfuryl Chloride

**Decomposition Reaction:**
\[ \text{SO}_2\text{Cl}_2 \rightarrow \text{SO}_2 + \text{Cl}_2 \]

**Conditions:**
- Temperature: 600 K

**Experimental Data:**
The following table represents the concentration of sulfuryl chloride \((\text{SO}_2\text{Cl}_2)\) over different time intervals:

| \([\text{SO}_2\text{Cl}_2]\), M | 3.55 × 10\(^-3\) | 2.35 × 10\(^-3\) | 1.55 × 10\(^-3\) | 1.02 × 10\(^-3\) |
|--------------------------------|------------------|------------------|------------------|------------------|
| **Time, min**                  | 0                | 148              | 296              | 444              |

**Calculation Task:**
Determine the average rate of disappearance of \(\text{SO}_2\text{Cl}_2\) using the concentration data from \( t = 0 \, \text{min} \) to \( t = 148 \, \text{min} \).

**Required Answer:**
The average rate of disappearance of \(\text{SO}_2\text{Cl}_2\) over the given time period is as follows:

\[ \text{Rate} = \frac{\Delta [\text{SO}_2\text{Cl}_2]}{\Delta t} \]

Where:
- \(\Delta [\text{SO}_2\text{Cl}_2] = (\text{Final concentration} - \text{Initial concentration})\)
- \(\Delta t = (\text{Final time} - \text{Initial time})\)

Substitute the values:
\[ \Delta [\text{SO}_2\text{Cl}_2] = 2.35 \times 10^{-3} \, \text{M} - 3.55 \times 10^{-3} \, \text{M} = -1.20 \times 10^{-3} \, \text{M} \]
\[ \Delta t = 148 \, \text{min} - 0 \, \text{min} = 148
Transcribed Image Text:### Gas Phase Decomposition of Sulfuryl Chloride **Decomposition Reaction:** \[ \text{SO}_2\text{Cl}_2 \rightarrow \text{SO}_2 + \text{Cl}_2 \] **Conditions:** - Temperature: 600 K **Experimental Data:** The following table represents the concentration of sulfuryl chloride \((\text{SO}_2\text{Cl}_2)\) over different time intervals: | \([\text{SO}_2\text{Cl}_2]\), M | 3.55 × 10\(^-3\) | 2.35 × 10\(^-3\) | 1.55 × 10\(^-3\) | 1.02 × 10\(^-3\) | |--------------------------------|------------------|------------------|------------------|------------------| | **Time, min** | 0 | 148 | 296 | 444 | **Calculation Task:** Determine the average rate of disappearance of \(\text{SO}_2\text{Cl}_2\) using the concentration data from \( t = 0 \, \text{min} \) to \( t = 148 \, \text{min} \). **Required Answer:** The average rate of disappearance of \(\text{SO}_2\text{Cl}_2\) over the given time period is as follows: \[ \text{Rate} = \frac{\Delta [\text{SO}_2\text{Cl}_2]}{\Delta t} \] Where: - \(\Delta [\text{SO}_2\text{Cl}_2] = (\text{Final concentration} - \text{Initial concentration})\) - \(\Delta t = (\text{Final time} - \text{Initial time})\) Substitute the values: \[ \Delta [\text{SO}_2\text{Cl}_2] = 2.35 \times 10^{-3} \, \text{M} - 3.55 \times 10^{-3} \, \text{M} = -1.20 \times 10^{-3} \, \text{M} \] \[ \Delta t = 148 \, \text{min} - 0 \, \text{min} = 148
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