The reaction 2NO(g) + Cl2 (9) → 2NOCI(g) was studied at –10°C. The following results were obtained where A[CL] Rate At [NO], (mol/L) 0.13 [Cl2]o (mol/L) Initial Rate (mol L-min) 0.13 0.40 0.13 0.26 0.79 0.26 0.26 3.16 a What is the rate law? (Use k for the rate constant. ) Rate = k[NO]°[Cl,]/ b What is the value of the rate constant? L? Rate constant = mol? - min
The reaction 2NO(g) + Cl2 (9) → 2NOCI(g) was studied at –10°C. The following results were obtained where A[CL] Rate At [NO], (mol/L) 0.13 [Cl2]o (mol/L) Initial Rate (mol L-min) 0.13 0.40 0.13 0.26 0.79 0.26 0.26 3.16 a What is the rate law? (Use k for the rate constant. ) Rate = k[NO]°[Cl,]/ b What is the value of the rate constant? L? Rate constant = mol? - min
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The reaction
2NO(g) + Cl2 (9) → 2NOCI(g)
was studied at –10°C. The following results were obtained where
A[CL]
Rate
At
[NO],
(mol/L)
0.13
[Cl2]o
(mol/L)
Initial Rate
(mol L-min)
0.13
0.40
0.13
0.26
0.79
0.26
0.26
3.16
a What is the rate law?
(Use k for the rate constant. )
Rate = k[NO]°[Cl,]/
b What is the value of the rate constant?
L?
Rate constant =
mol? - min](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa0bb861a-a74a-4663-bbeb-0fca4422e7c0%2Fa8b4c51f-635f-402f-b464-d29a21d4621c%2Fltl4w_processed.png&w=3840&q=75)
Transcribed Image Text:The reaction
2NO(g) + Cl2 (9) → 2NOCI(g)
was studied at –10°C. The following results were obtained where
A[CL]
Rate
At
[NO],
(mol/L)
0.13
[Cl2]o
(mol/L)
Initial Rate
(mol L-min)
0.13
0.40
0.13
0.26
0.79
0.26
0.26
3.16
a What is the rate law?
(Use k for the rate constant. )
Rate = k[NO]°[Cl,]/
b What is the value of the rate constant?
L?
Rate constant =
mol? - min
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