For the reaction: BrO³- (aq) + 5Br (aq) + 8H+ (aq) → 3Br₂(e) + H₂O(l) The initial rate of the reaction has been measured at the reactant concentrat show: Trial [BrO3] (mol/L) 0.10 0.20 0.10 0.10 1 2 3 4 [H*] (mol/L) 0.10 0.10 0.20 0.10 [Br] (mol/L) 0.10 0.10 0.10 0.20 Initial r (mol/L. 8.0 16 16 32 Please do not include any units in your answer. Just the numerical value. The value for k will be: AL³/mol³-s
For the reaction: BrO³- (aq) + 5Br (aq) + 8H+ (aq) → 3Br₂(e) + H₂O(l) The initial rate of the reaction has been measured at the reactant concentrat show: Trial [BrO3] (mol/L) 0.10 0.20 0.10 0.10 1 2 3 4 [H*] (mol/L) 0.10 0.10 0.20 0.10 [Br] (mol/L) 0.10 0.10 0.10 0.20 Initial r (mol/L. 8.0 16 16 32 Please do not include any units in your answer. Just the numerical value. The value for k will be: AL³/mol³-s
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For the reaction: BrO3- (aq) + 5Br (aq) + 8H(aq) → 3Br₂(e) + H₂O(e)
The initial rate of the reaction has been measured at the reactant concentratic
show:
Trial [BrO3]
(mol/L)
0.10
12
3
4
Quest
0.20
0.10
0.10
14
[H*]
(mol/L)
0.10
0.10
0.20
0.10
[Br]
(mol/L)
0.10
0.10
0.10
0.20
Please do not include any units in your answer. Just the numerical value.
The value for k will be:
Initial ra
(mol/L-s
8.0
16
A/L³/mol³.s
16
32](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba6eb982-7a90-499e-8737-81d934f48366%2F36ca2234-4db0-45b3-bc13-f9e602ae70ed%2F3oik6ii_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the reaction: BrO3- (aq) + 5Br (aq) + 8H(aq) → 3Br₂(e) + H₂O(e)
The initial rate of the reaction has been measured at the reactant concentratic
show:
Trial [BrO3]
(mol/L)
0.10
12
3
4
Quest
0.20
0.10
0.10
14
[H*]
(mol/L)
0.10
0.10
0.20
0.10
[Br]
(mol/L)
0.10
0.10
0.10
0.20
Please do not include any units in your answer. Just the numerical value.
The value for k will be:
Initial ra
(mol/L-s
8.0
16
A/L³/mol³.s
16
32
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