Temperature, °C 3.0 2.0 1.0 0.0 4.0 5.0 8.0 7.0 6.0 0 In an experiment, the freezing point curve of pure benzene is in Trial I. When 0.9584 g of the nonionic solute camphor was dissolved in 16.2051 g of benzene, the data in Trial II was obtained. An additional 0.8246 g of camphor was added to the solution and the data in Trial III was obtained. Freezing Point Depression Temperature vs. Time 5 Time, min Trial I Trial II Trial Ill 10 Calculate the average molar mass. AF = i krm a. Determine the freezing points of runs I, II and III. 159 Trial I: Trial II: b. Calculate the experimental molar mass of camphor using Trials I and II. 5,4= Trial III: c. Calculate the experimental molar mass of camphor using Trials I and III. 5.4 3.4 1.7 Continued

Temperature, °C 3.0 2.0 1.0 0.0 4.0 5.0 8.0 7.0 6.0 0 In an experiment, the freezing point curve of pure benzene is in Trial I. When 0.9584 g of the nonionic solute camphor was dissolved in 16.2051 g of benzene, the data in Trial II was obtained. An additional 0.8246 g of camphor was added to the solution and the data in Trial III was obtained. Freezing Point Depression Temperature vs. Time 5 Time, min Trial I Trial II Trial Ill 10 Calculate the average molar mass. AF = i krm a. Determine the freezing points of runs I, II and III. 159 Trial I: Trial II: b. Calculate the experimental molar mass of camphor using Trials I and II. 5,4= Trial III: c. Calculate the experimental molar mass of camphor using Trials I and III. 5.4 3.4 1.7 Continued

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Temperature, °C
3.0
2.0
1.0
0.0
4.0
5.0
8.0
7.0
6.0
0
In an experiment, the freezing point curve of pure benzene is in Trial I. When 0.9584 g
of the nonionic solute camphor was dissolved in 16.2051 g of benzene, the data in Trial
II was obtained. An additional 0.8246 g of camphor was added to the solution and the
data in Trial III was obtained.
Freezing Point Depression
Temperature vs. Time
5
Time, min
Trial I
Trial II
Trial Ill
10
Calculate the average molar mass.
AF = i krm
a. Determine the freezing
points of runs I, II and
III.
159
Trial I:
Trial II:
b. Calculate the experimental molar mass of camphor using Trials I and II.
5,4=
Trial III:
c. Calculate the experimental molar mass of camphor using Trials I and III.
5.4
3.4
1.7
Continued

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