A solution consists of 39.2 g of ethanol (CH3CH2OH), 139.8 g water, and has a volume of 185 mL. Calculate the weight percent of CH3CH2OH, the molality of CH3CH2OH, the mole fraction of CH3CH2OH, and the molarity of CH3CH2OH in the solution. weight percent = % molality = m mole fraction molarity = M =
A solution consists of 39.2 g of ethanol (CH3CH2OH), 139.8 g water, and has a volume of 185 mL. Calculate the weight percent of CH3CH2OH, the molality of CH3CH2OH, the mole fraction of CH3CH2OH, and the molarity of CH3CH2OH in the solution. weight percent = % molality = m mole fraction molarity = M =
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.17QE
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Question
![A solution consists of 39.2 g of
ethanol (CH3CH2OH), 139.8 g
water, and has a volume of 185
mL. Calculate the weight
percent of CH3CH2OH, the
molality of CH3CH2OH, the
mole fraction of CH3CH2OH,
and the molarity of CH3CH2OH
in the solution. weight percent
= % molality = m mole fraction
molarity = M
=
||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe9ed106a-49f4-4b72-95e9-7c8fb36f659b%2F022dacf0-d2f1-4e69-a5f0-e2a9dfb6f6bb%2F4hj4xxn_processed.png&w=3840&q=75)
Transcribed Image Text:A solution consists of 39.2 g of
ethanol (CH3CH2OH), 139.8 g
water, and has a volume of 185
mL. Calculate the weight
percent of CH3CH2OH, the
molality of CH3CH2OH, the
mole fraction of CH3CH2OH,
and the molarity of CH3CH2OH
in the solution. weight percent
= % molality = m mole fraction
molarity = M
=
||
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