Calculate the molality of a solution that contains 1.73 g carvone in 13.4 mL of ethanol (density 0.7893 g/mL). Assume that carvone is nonvolatile at the normal boiling point of ethanol and that it is a nonelectrolyte. Molality = m O See Hint Using your answer from Part 2, calculate the change in boiling point and the actual boiling point for the solution. The normal boiling point of ethanol is 78.24°C, and K, for this solvent is equal to 1.22°C/m. AT, for the solution = °C and Tp = °C

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### Calculating the Molality and Boiling Point Elevation

#### Problem Statement:
Calculate the molality of a solution that contains 1.73 g of carvone in 13.4 mL of ethanol (density 0.7893 g/mL). Assume that carvone is nonvolatile at the normal boiling point of ethanol and that it is a nonelectrolyte.

**Molality =** ____ m

#### Discussion:
Using your answer from Part 2, calculate the change in boiling point and the actual boiling point for the solution. The normal boiling point of ethanol is 78.24°C, and \( K_b \) for this solvent is equal to 1.22°C/m.

\[ \Delta T_b \text{ for the solution} = \] ____ °C

and

\[ T_b = \] ____ °C
Transcribed Image Text:### Calculating the Molality and Boiling Point Elevation #### Problem Statement: Calculate the molality of a solution that contains 1.73 g of carvone in 13.4 mL of ethanol (density 0.7893 g/mL). Assume that carvone is nonvolatile at the normal boiling point of ethanol and that it is a nonelectrolyte. **Molality =** ____ m #### Discussion: Using your answer from Part 2, calculate the change in boiling point and the actual boiling point for the solution. The normal boiling point of ethanol is 78.24°C, and \( K_b \) for this solvent is equal to 1.22°C/m. \[ \Delta T_b \text{ for the solution} = \] ____ °C and \[ T_b = \] ____ °C
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