A solution containing 6.314 g of a non-volatile organic solute dissolved in 100.00 g of toluene boils at 384.72 K at 1 bar of pressure. The boiling point of pure toluene is 383.75 K and AvapH = 38.06 kJ/mol for benzene. (a) What is the boiling point elevation constant for toluene? (units: kg.K/mol) (b) What is the molar mass (g/mol) of the unknown solute?
A solution containing 6.314 g of a non-volatile organic solute dissolved in 100.00 g of toluene boils at 384.72 K at 1 bar of pressure. The boiling point of pure toluene is 383.75 K and AvapH = 38.06 kJ/mol for benzene. (a) What is the boiling point elevation constant for toluene? (units: kg.K/mol) (b) What is the molar mass (g/mol) of the unknown solute?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A solution containing 6.314 g of a non-volatile organic solute dissolved in 100.00 g of toluene boils at 384.72 K at 1 bar of pressure. The boiling point of pure toluene is 383.75 K and Δ_vapH = 38.06 kJ/mol for benzene.
(a) What is the boiling point elevation constant for toluene? (units: kg·K/mol)
(b) What is the molar mass (g/mol) of the unknown solute?
**Explanation:**
This problem involves the concept of boiling point elevation, which is a colligative property of solutions. Such properties depend on the number of solute particles in a solution, not their identity. Since toluene is the solvent, and a non-volatile solute is involved, its boiling point increases when the solute is added. The problem asks for the boiling point elevation constant, a value unique to toluene, and for the molar mass of the solute, which requires calculation.
No graphs or diagrams are present to be explained further.
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