(solutions) calculate freezing temp of 3.15g (C10H8) in 10.40g benzene which has a normal freezing temp of 5.5C. (Kf is 5.12C Kg/mol); this must be van’t hoff? Calculate the freezing point of a solution of 3.15 g of naphthalene (C,oHs) in 10.40 g of benzene.The freezing point of pure benzene is 5.5°C.KF = 5.12°C kg/mol.2.2Submit AnswerIncorrect. Tries 2/99 Previous TriesCalculate the boiling_point of the above solution.The boiling point of pure benzene is 80.1°C.K = 2.53°C kg/mol.°CSubmit AnswerTries 0/99

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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(solutions) calculate freezing temp of 3.15g (C10H8) in 10.40g benzene which has a normal freezing temp of 5.5C. (Kf is 5.12C Kg/mol); this must be van’t hoff?

Calculate the freezing point of a solution of 3.15 g of naphthalene (C,oHs) in 10.40 g of benzene.
The freezing point of pure benzene is 5.5°C.
KF = 5.12°C kg/mol.
2.2
Submit Answer
Incorrect. Tries 2/99 Previous Tries
Calculate the boiling_point of the above solution.
The boiling point of pure benzene is 80.1°C.
K = 2.53°C kg/mol.
°C
Submit Answer
Tries 0/99

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