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%24 %23 3. 2. Mixing) (1) NaCl + NAOH Na+,Cl- Na+,OH- (2) HCI + NaOH H+,Cl- Na+,OH- (3) HCI + NH3 ()( ) H+,Cl- negligible ionisation (4) NH3 + HC2H3O2 Weak electrolýtes, there' is no ions because of their ionisation is negligible bet we can observe conductivity due to partial ionisaton Comment on the above reaction with the largest conductivity change. Explain what is happening at the molecular level to have such a large increase in conductivity. lonic Reactions:. A Write the net ionic equations for each reaction. 1. (FeC13(aq)+3NAOH(aq)–Fe(OH)3+3NACI Fe3+3Cl+3Na+30H–Fe(OH)3(s)+3Na Fe3(aq)+3OH(aq)–Fe(OH)3(s) HCI(aq)+NaOH(aq)–NaCl(aq)+H2O(I) H(aq)+OH(aq)–H2O(I) 3CUSO4(aq) + 2N23PO4(aq)–Cu3(PO4)2(s)+3NA2SO4(aq) 3Cu(aq) + 2PO4(aq)–Cu3(PO4)2(S) 000 000 F1 F2 F3 DD F4 F5 # %

%24 %23 3. 2. Mixing) (1) NaCl + NAOH Na+,Cl- Na+,OH- (2) HCI + NaOH H+,Cl- Na+,OH- (3) HCI + NH3 ()( ) H+,Cl- negligible ionisation (4) NH3 + HC2H3O2 Weak electrolýtes, there' is no ions because of their ionisation is negligible bet we can observe conductivity due to partial ionisaton Comment on the above reaction with the largest conductivity change. Explain what is happening at the molecular level to have such a large increase in conductivity. lonic Reactions:. A Write the net ionic equations for each reaction. 1. (FeC13(aq)+3NAOH(aq)–Fe(OH)3+3NACI Fe3+3Cl+3Na+30H–Fe(OH)3(s)+3Na Fe3(aq)+3OH(aq)–Fe(OH)3(s) HCI(aq)+NaOH(aq)–NaCl(aq)+H2O(I) H(aq)+OH(aq)–H2O(I) 3CUSO4(aq) + 2N23PO4(aq)–Cu3(PO4)2(s)+3NA2SO4(aq) 3Cu(aq) + 2PO4(aq)–Cu3(PO4)2(S) 000 000 F1 F2 F3 DD F4 F5 # %

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Comment on the above reaction with the largest conductivity change. Explain what is happening at the molecular level to have such a large increase in codutivity 

%24 %23 3. 2. Mixing) (1) NaCl + NAOH Na+,Cl- Na+,OH- (2) HCI + NaOH H+,Cl- Na+,OH- (3) HCI + NH3 ()( ) H+,Cl- negligible ionisation (4) NH3 + HC2H3O2 Weak electrolýtes, there' is no ions because of their ionisation is negligible bet we can observe conductivity due to partial ionisaton Comment on the above reaction with the largest conductivity change. Explain what is happening at the molecular level to have such a large increase in conductivity. lonic Reactions:. A Write the net ionic equations for each reaction. 1. (FeC13(aq)+3NAOH(aq)–Fe(OH)3+3NACI Fe3+3Cl+3Na+30H–Fe(OH)3(s)+3Na Fe3(aq)+3OH(aq)–Fe(OH)3(s) HCI(aq)+NaOH(aq)–NaCl(aq)+H2O(I) H(aq)+OH(aq)–H2O(I) 3CUSO4(aq) + 2N23PO4(aq)–Cu3(PO4)2(s)+3NA2SO4(aq) 3Cu(aq) + 2PO4(aq)–Cu3(PO4)2(S) 000 000 F1 F2 F3 DD F4 F5 # %
Transcribed Image Text:%24 %23 3. 2. Mixing) (1) NaCl + NAOH Na+,Cl- Na+,OH- (2) HCI + NaOH H+,Cl- Na+,OH- (3) HCI + NH3 ()( ) H+,Cl- negligible ionisation (4) NH3 + HC2H3O2 Weak electrolýtes, there' is no ions because of their ionisation is negligible bet we can observe conductivity due to partial ionisaton Comment on the above reaction with the largest conductivity change. Explain what is happening at the molecular level to have such a large increase in conductivity. lonic Reactions:. A Write the net ionic equations for each reaction. 1. (FeC13(aq)+3NAOH(aq)–Fe(OH)3+3NACI Fe3+3Cl+3Na+30H–Fe(OH)3(s)+3Na Fe3(aq)+3OH(aq)–Fe(OH)3(s) HCI(aq)+NaOH(aq)–NaCl(aq)+H2O(I) H(aq)+OH(aq)–H2O(I) 3CUSO4(aq) + 2N23PO4(aq)–Cu3(PO4)2(s)+3NA2SO4(aq) 3Cu(aq) + 2PO4(aq)–Cu3(PO4)2(S) 000 000 F1 F2 F3 DD F4 F5 # %
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