Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Expert Solution
Step 1
Since the solution is aqueous. Hence the depression in freezing point is
depression in freezing point = freezing point of water - freezing point of solution = 0 - (-0.88) = 0.88 oC
Step 2
Since depression in freezing point is also given by
depression in freezing point = i X Kf X m
where i = Van't Hoff factor = 1 ( since sucrose is not electrolyte solute)
Kf = depression in freezing point constant = 1.86 oC m-1
m = molality of the solute
Hence substituting the values we get
0.88 = 1 X 1.86 X m
=> m = molality of sucrose = 0.473 mol/Kg
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