Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![makes it difficult to compare Kp values directly.
HgS
Kp
1.6 x 104
Cus
8.5 x 1045
Ag:S
1.6 x 10
BizS
Ix 103
Pb;(PO4):
1 x 104](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe7d69837-8ca1-4e3f-a9f1-1c248c21443a%2F000ebc04-c58c-4d87-aa24-be36cc32bd5d%2Fb8nqdx.jpeg&w=3840&q=75)
Transcribed Image Text:makes it difficult to compare Kp values directly.
HgS
Kp
1.6 x 104
Cus
8.5 x 1045
Ag:S
1.6 x 10
BizS
Ix 103
Pb;(PO4):
1 x 104
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Ksp : At normal temperature, if the solubility of a salt is 0.1mol / Lit then that salt is called sparingly soluble salt. The product of the solubility of all the ions is called solubility product or Ksp .
Step 2
Let, AB is a sparingly soluble salt in water. Then its equilibrium should be:
Where Ksp is called solubility product of sparingly soluble salt AB.
Let S be the solubility.
So in solution [ Ay+ ]= x ×S mol/Lit. And [B x- ]= y ×S.
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