CH3ONA CH3OH H in \CH3 H3C CH3

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the reaction below:

Draw the major organic structure.
This image depicts a chemical reaction involving an epoxide. The structure on the left is an epoxide with an oxygen atom forming a three-membered ring with two adjacent carbon atoms. The stereochemistry is shown with wedge and dash bonds, indicating the three-dimensional arrangement of the groups around the carbon atoms. The substituents include a hydrogen (H), two methyl groups (CH₃), and an ether oxygen (O).

The arrow indicates a chemical reaction, with conditions specified above and below it. Above the arrow is "CH₃ONa," which is sodium methoxide, a strong base and nucleophile. Below the arrow is "CH₃OH," methanol, a solvent. This suggests a nucleophilic ring-opening reaction catalyzed by sodium methoxide in the presence of methanol.

In this reaction, the epoxide is likely to open up, resulting in the formation of a new product where the nucleophile, methoxide, attacks the less hindered carbon atom in the epoxide ring. This is a typical reaction mechanism for an epoxide under basic conditions.
Transcribed Image Text:This image depicts a chemical reaction involving an epoxide. The structure on the left is an epoxide with an oxygen atom forming a three-membered ring with two adjacent carbon atoms. The stereochemistry is shown with wedge and dash bonds, indicating the three-dimensional arrangement of the groups around the carbon atoms. The substituents include a hydrogen (H), two methyl groups (CH₃), and an ether oxygen (O). The arrow indicates a chemical reaction, with conditions specified above and below it. Above the arrow is "CH₃ONa," which is sodium methoxide, a strong base and nucleophile. Below the arrow is "CH₃OH," methanol, a solvent. This suggests a nucleophilic ring-opening reaction catalyzed by sodium methoxide in the presence of methanol. In this reaction, the epoxide is likely to open up, resulting in the formation of a new product where the nucleophile, methoxide, attacks the less hindered carbon atom in the epoxide ring. This is a typical reaction mechanism for an epoxide under basic conditions.
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