2) Draw 3 different molecules: 1. One with a primary carbon leaving group 2. One with a secondary carbon leaving group 3. One with a tertiary carbon leaving group Explain which one is best suited for the bimolecular substitution (SN2) reaction any why.
2) Draw 3 different molecules: 1. One with a primary carbon leaving group 2. One with a secondary carbon leaving group 3. One with a tertiary carbon leaving group Explain which one is best suited for the bimolecular substitution (SN2) reaction any why.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question

Transcribed Image Text:**Exercise: Drawing Molecular Structures and Reaction Suitability**
**Task:** Draw 3 different molecules:
1. **Molecule with a Primary Carbon Leaving Group**
2. **Molecule with a Secondary Carbon Leaving Group**
3. **Molecule with a Tertiary Carbon Leaving Group**
**Question:** Explain which one is best suited for the bimolecular substitution (SN2) reaction and why.
---
**Explanation for Educational Context:**
To determine which molecule is best suited for an SN2 reaction, consider the structure of the molecules:
- **Primary Carbon Leaving Group:** Typically, SN2 reactions are most efficient with primary carbons. This is because there is less steric hindrance, allowing the nucleophile to attack more easily.
- **Secondary Carbon Leaving Group:** SN2 reactions can occur, but are less favorable than with primary carbons due to increased steric hindrance.
- **Tertiary Carbon Leaving Group:** SN2 reactions are least favorable with tertiary carbons because of significant steric hindrance. Tertiary carbons favor SN1 reactions instead.
**Conclusion:** Molecules with primary carbon leaving groups are best suited for SN2 reactions due to minimal steric hindrance, allowing for a more efficient nucleophilic attack.
Expert Solution

Step 1
Draw the 3 different molecules :
1. One with a primary carbon leaving group.
2.One with a secondary carbon leaving group.
3. One with a tertiary carbon leaving group.
Which one is best suited for SN2 reaction & why ?
Step by step
Solved in 6 steps with 1 images
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