CH3 NaOH

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For each section, circle the mechanism from the two options given (SN1 or SN2) and draw the main organic product resulting from that mechanism. Indicate the stereochemistry and if two configurational isomers form, draw both. 

The image shows a chemical reaction diagram featuring a substrate and a reagent. 

**Description of the Reaction:**

- **Substrate:** The starting compound is a phenyl-substituted 2-iodopropane (an iodide derivative). It features a benzene ring attached to a two-carbon chain with an iodine atom and a methyl group (CH₃) on the chiral carbon.
  
- **Reagent:** Sodium hydroxide (NaOH), a common strong base, is used in this reaction.

- **Reaction Arrow:** The arrow indicates the transformation of the substrate when treated with the reagent.

**Explanation of the Reaction:**

This reaction likely involves the nucleophilic substitution of the iodine atom by a hydroxide ion from NaOH, leading to the formation of an alcohol. The hydroxide ion acts as a nucleophile, replacing the iodine on the central chiral carbon atom. The expected product would be a secondary alcohol with the same benzene ring and methyl group attached.
Transcribed Image Text:The image shows a chemical reaction diagram featuring a substrate and a reagent. **Description of the Reaction:** - **Substrate:** The starting compound is a phenyl-substituted 2-iodopropane (an iodide derivative). It features a benzene ring attached to a two-carbon chain with an iodine atom and a methyl group (CH₃) on the chiral carbon. - **Reagent:** Sodium hydroxide (NaOH), a common strong base, is used in this reaction. - **Reaction Arrow:** The arrow indicates the transformation of the substrate when treated with the reagent. **Explanation of the Reaction:** This reaction likely involves the nucleophilic substitution of the iodine atom by a hydroxide ion from NaOH, leading to the formation of an alcohol. The hydroxide ion acts as a nucleophile, replacing the iodine on the central chiral carbon atom. The expected product would be a secondary alcohol with the same benzene ring and methyl group attached.
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