Draw both chair conformations of the starting alkyl bromide. Indicate which conformation, if either is more stable. Briefly justify your answer. b)  The starting alkyl halide has two chiral carbons. What are the configurations (R/S) at each of these carbons? c)  Identify the mechanism (E1/E2) which reactions 1, 2, and 3 proceed by. d)  Provide mechanisms that explain the products formed in reactions 1, 2, and 3. All electron movement must be shown in order to receive full credit. e)  Indicate which product is the major and which product is the minor in reactions 2 and 3. Briefly justify your answer.

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a)  Draw both chair conformations of the starting alkyl bromide. Indicate which conformation, if either is more stable. Briefly justify your answer.

b)  The starting alkyl halide has two chiral carbons. What are the configurations (R/S) at each of these carbons?

c)  Identify the mechanism (E1/E2) which reactions 1, 2, and 3 proceed by.

d)  Provide mechanisms that explain the products formed in reactions 1, 2, and 3. All electron movement must be shown in order to receive full credit.

e)  Indicate which product is the major and which product is the minor in reactions 2 and 3. Briefly justify your answer.

**Transcription for Educational Website:**

**Title: Elimination Reaction Example**

**Reaction Overview:**

- **Starting Material:** A cyclohexane ring with a bromine (Br) atom and two methyl (CH₃) groups attached. The Br atom and one CH₃ group are on adjacent carbons, with both groups in a wedge conformation.
  
- **Reagent and Conditions:** Sodium ethoxide (Na⁺ -OCH₂CH₃) is used as a base in the presence of heat.

**Reaction Process:**

- The sodium ethoxide acts as a strong base, promoting the elimination of the bromine atom and forming an alkene.

- **Product Formation:** The reaction results in the formation of a cyclohexene ring with two CH₃ groups, indicating a double bond is introduced between the carbon that originally held the Br and its adjacent carbon.

- **Byproducts:** Sodium bromide (NaBr) and ethyl alcohol (CH₃CH₂OH) are also formed.

**Graphical Explanation:**

- The reaction scheme is shown with molecular structures before and after the reaction.
  
- Arrows indicate the transition from starting materials to products and byproducts.

- The notation "only product" highlights that the reaction is selective, yielding a single alkene product.

This reaction illustrates a typical elimination mechanism where a halogen leaves the molecule, facilitating the formation of a double bond and resulting in the release of side products.
Transcribed Image Text:**Transcription for Educational Website:** **Title: Elimination Reaction Example** **Reaction Overview:** - **Starting Material:** A cyclohexane ring with a bromine (Br) atom and two methyl (CH₃) groups attached. The Br atom and one CH₃ group are on adjacent carbons, with both groups in a wedge conformation. - **Reagent and Conditions:** Sodium ethoxide (Na⁺ -OCH₂CH₃) is used as a base in the presence of heat. **Reaction Process:** - The sodium ethoxide acts as a strong base, promoting the elimination of the bromine atom and forming an alkene. - **Product Formation:** The reaction results in the formation of a cyclohexene ring with two CH₃ groups, indicating a double bond is introduced between the carbon that originally held the Br and its adjacent carbon. - **Byproducts:** Sodium bromide (NaBr) and ethyl alcohol (CH₃CH₂OH) are also formed. **Graphical Explanation:** - The reaction scheme is shown with molecular structures before and after the reaction. - Arrows indicate the transition from starting materials to products and byproducts. - The notation "only product" highlights that the reaction is selective, yielding a single alkene product. This reaction illustrates a typical elimination mechanism where a halogen leaves the molecule, facilitating the formation of a double bond and resulting in the release of side products.
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