CH12 + Oz→ CO, 4 H,0 Atomic masses: C = 12.01, H=1.01, O=16.00, N=14.01 The chemical equation is not balanced, so you have to balance the equation first before you can even start answering the questions below. 2a. If exactly 5.50 moles of pentane reacted, how many moles of oxygen (O2) gas were needed? 2b. If 22.5 grams of O2 completely reacted with enough pentane, how many moles of H2O were produced? 2c. If 34.2 grams of pentane completely reacted with enough oxygen gas, how many_grams (g) of CO2 were produced?
CH12 + Oz→ CO, 4 H,0 Atomic masses: C = 12.01, H=1.01, O=16.00, N=14.01 The chemical equation is not balanced, so you have to balance the equation first before you can even start answering the questions below. 2a. If exactly 5.50 moles of pentane reacted, how many moles of oxygen (O2) gas were needed? 2b. If 22.5 grams of O2 completely reacted with enough pentane, how many moles of H2O were produced? 2c. If 34.2 grams of pentane completely reacted with enough oxygen gas, how many_grams (g) of CO2 were produced?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer and show your work for sub parts 2a, 2b and 2c
![**Problem 2**
The gaseous hydrocarbon, pentane (C₅H₁₂), burns with oxygen gas (O₂) to form the products carbon dioxide and water according to the equation below:
\[ \text{C}_5\text{H}_{12} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
**Atomic masses:**
C = 12.01, H = 1.01, O = 16.00, N = 14.01
The chemical equation is not balanced, so you have to balance the equation first before you can even start answering the questions below.
**Questions:**
2a. If exactly 5.50 moles of pentane reacted, *how many moles of oxygen (O₂) gas were needed*?
2b. If 22.5 grams of O₂ completely reacted with enough pentane, *how many moles of H₂O were produced*?
2c. If 34.2 grams of pentane completely reacted with enough oxygen gas, *how many grams (g) of CO₂ were produced*?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5770d38-7bc6-4305-a1b7-fd2f8a59c389%2F20d0a8bb-751f-46e4-afbe-b643cf87a99a%2Flpqvzl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 2**
The gaseous hydrocarbon, pentane (C₅H₁₂), burns with oxygen gas (O₂) to form the products carbon dioxide and water according to the equation below:
\[ \text{C}_5\text{H}_{12} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
**Atomic masses:**
C = 12.01, H = 1.01, O = 16.00, N = 14.01
The chemical equation is not balanced, so you have to balance the equation first before you can even start answering the questions below.
**Questions:**
2a. If exactly 5.50 moles of pentane reacted, *how many moles of oxygen (O₂) gas were needed*?
2b. If 22.5 grams of O₂ completely reacted with enough pentane, *how many moles of H₂O were produced*?
2c. If 34.2 grams of pentane completely reacted with enough oxygen gas, *how many grams (g) of CO₂ were produced*?
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