Ch CH¿CH2CH,CH; CH;CHCH,CH3 light ČI (1:1 Moar) i) Name the general type of reaction shown above. ii) The reaction proceeds via a free-radical mechanism. Show the mechanism for the formation of the chlorinated product above. iii) The chlorinated product has one chiral centre. Draw two enantiomers of this compound using perspective diagrams. iv) Identify the absolute configuration for each isomer. v) Give one way in which the two enantiomers could be distinguished.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Ch
CH¿CH2CH,CH;
CH;CHCH,CH3
light
ČI
(1:1 Moar)
i) Name the general type of reaction shown above.
ii) The reaction proceeds via a free-radical mechanism. Show the mechanism for the formation of
the chlorinated product above.
iii) The chlorinated product has one chiral centre. Draw two enantiomers of this compound using
perspective diagrams.
iv) Identify the absolute configuration for each isomer.
v) Give one way in which the two enantiomers could be distinguished.
Transcribed Image Text:Ch CH¿CH2CH,CH; CH;CHCH,CH3 light ČI (1:1 Moar) i) Name the general type of reaction shown above. ii) The reaction proceeds via a free-radical mechanism. Show the mechanism for the formation of the chlorinated product above. iii) The chlorinated product has one chiral centre. Draw two enantiomers of this compound using perspective diagrams. iv) Identify the absolute configuration for each isomer. v) Give one way in which the two enantiomers could be distinguished.
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