Cd(s) + Fe2*(aq) → Cd²*(aq) + Fe(s) E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd2+] = 0.010 M. %3D E = V Will the reaction occur spontaneously at these conditions? yes no
Cd(s) + Fe2*(aq) → Cd²*(aq) + Fe(s) E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd2+] = 0.010 M. %3D E = V Will the reaction occur spontaneously at these conditions? yes no
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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.127QP
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Question
![Be sure to answer all parts.
Consider the following reaction:
Cd(s) + Fe2*(aq) -
Cd2*(aq) + Fe(s)
E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V
Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd²*] = 0.010 M.
E =
V
Will the reaction occur spontaneously at these conditions?
yes
no
cannot predict](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b9a5e3a-13c3-426b-8948-52c1d49e3a86%2F814b37de-3e05-4ae0-b287-dfea482595bd%2F76v9oet_processed.png&w=3840&q=75)
Transcribed Image Text:Be sure to answer all parts.
Consider the following reaction:
Cd(s) + Fe2*(aq) -
Cd2*(aq) + Fe(s)
E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V
Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd²*] = 0.010 M.
E =
V
Will the reaction occur spontaneously at these conditions?
yes
no
cannot predict
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