Cd(s) + Fe2*(aq) → Cd²*(aq) + Fe(s) E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd2+] = 0.010 M. %3D E = V Will the reaction occur spontaneously at these conditions? yes no

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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.127QP
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Be sure to answer all parts.
Consider the following reaction:
Cd(s) + Fe2*(aq) -
Cd2*(aq) + Fe(s)
E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V
Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd²*] = 0.010 M.
E =
V
Will the reaction occur spontaneously at these conditions?
yes
no
cannot predict
Transcribed Image Text:Be sure to answer all parts. Consider the following reaction: Cd(s) + Fe2*(aq) - Cd2*(aq) + Fe(s) E° (Fe2+ / Fe) = -0.4400 V, E° (Cd²+ / Cd) = -0.4000 V Calculate the emf for this reaction at 298 K if [Fe²*] = 0.75 M and [Cd²*] = 0.010 M. E = V Will the reaction occur spontaneously at these conditions? yes no cannot predict
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