Calculate AG° and K at 25°C for the reactions.7H2O +2 Cr43 Cl2 Cr2 0,2- +6 Cl + 14H ea.=0.03 V%3DcellAGkJK =b.Cu2+ (aq) + Mn(s) Mn²+ (aq) + Cu(s) e = 1.52 VAGkJ%3DCl2 (g) + 2 Br (aq) Br2 (g) +2°CI¯ (aq) e° = 0.27 Vс.AGkJK =d.3H2O(1) + 5 IO4 (ag) + 2 Mn2+ (ag) = 5 IO3 (aq) + 2 MnO4 (aq) + 6H* (aq)= 0.09 VcellAGkJK:ot12:49 PM12/6/2021earch

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Calculate AG and K at 25°C for the reactions. 7H2O+2 Cr43 Cl2 Cr20,2- +6 Cl +14H+ e = 0.03 V a. cell AG %3D kJ K = b. Cu+ (aq) + Mn(s)Mn2+ (aq) + Cu(s) e = 1.52 V AG kJ K = Cl2 (9) + 2 Br (ag) Br2 (g) + 2CI (aq) e = 0.27 V с. %3D AG kJ %3D K =

Calculate AG and K at 25°C for the reactions. 7H2O+2 Cr43 Cl2 Cr20,2- +6 Cl +14H+ e = 0.03 V a. cell AG %3D kJ K = b. Cu+ (aq) + Mn(s)Mn2+ (aq) + Cu(s) e = 1.52 V AG kJ K = Cl2 (9) + 2 Br (ag) Br2 (g) + 2CI (aq) e = 0.27 V с. %3D AG kJ %3D K =

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Calculate AG° and K at 25°C for the reactions.
7H2O +2 Cr43 Cl2 Cr2 0,2- +6 Cl + 14H e
a.
=0.03 V
%3D
cell
AG
kJ
K =
b.
Cu2+ (aq) + Mn(s) Mn²+ (aq) + Cu(s) e = 1.52 V
AG
kJ
%3D
Cl2 (g) + 2 Br (aq) Br2 (g) +2°CI¯ (aq) e° = 0.27 V
с.
AG
kJ
K =
d.
3H2O(1) + 5 IO4 (ag) + 2 Mn2+ (ag) = 5 IO3 (aq) + 2 MnO4 (aq) + 6H* (aq)
= 0.09 V
cell
AG
kJ
K:
ot
12:49 PM
12/6/2021
earch

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