Consider the following redox half-reaction at 25 °C: MnO4 (aq) + 8 H* (aq) + 5 e¯ → Mn²* (aq) + 4 H2O (I) E° = +1.51 V For a ratio of [Mn²*] : [MnO4¯]] = 1000:1, what must the pH of the solution be to give a value of the cell potential of E = +1.45 V? R = 8.314 J/mol.K F = 96485 C/mol Data needed:
Consider the following redox half-reaction at 25 °C: MnO4 (aq) + 8 H* (aq) + 5 e¯ → Mn²* (aq) + 4 H2O (I) E° = +1.51 V For a ratio of [Mn²*] : [MnO4¯]] = 1000:1, what must the pH of the solution be to give a value of the cell potential of E = +1.45 V? R = 8.314 J/mol.K F = 96485 C/mol Data needed:
Chemistry
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Chapter1: Chemical Foundations
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![Consider the following redox half-reaction at 25 °C:
MnO4- (aq) + 8 H* (aq) + 5 e¯ - Mn2* (aq) + 4 H20 (I)
E° = +1.51 V
For a ratio of [Mn²*] : [MnO4¯]] = 1000:1, what must the pH of the solution be to give a value of the
cell potential of E = +1.45 V?
R = 8.314 J/mol.K
F = 96485 C/mol
Data needed:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ea92b8c-1f5c-438d-953a-ce2c9c580f93%2F7f83ed06-909f-40b4-82f9-7ac840cbaaf6%2Fo0y3uoo_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the following redox half-reaction at 25 °C:
MnO4- (aq) + 8 H* (aq) + 5 e¯ - Mn2* (aq) + 4 H20 (I)
E° = +1.51 V
For a ratio of [Mn²*] : [MnO4¯]] = 1000:1, what must the pH of the solution be to give a value of the
cell potential of E = +1.45 V?
R = 8.314 J/mol.K
F = 96485 C/mol
Data needed:
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