Calculate the Eqalibium constant (K) with the complexation reaction, In a galvanic cell. Ammonia was added tocoppersolution and formed complex I need to find the amount of free ammonia and free copper ions. use log k value incalculatons and nernst equation.cell looks like this :Cu(s)I (copperions, aq)1M: NH3 (4M) II (copperion) 0.1M I Cu(s)Measured EMS = +0.407 V, find molar ratio and calculate the K value. 1 part of 1 M copperions was added with 9 partsof 4 M Ammonia. Thank you a tons!

The information provided describes a galvanic cell with a copper electrode and a copper ammonia…

Answered: Calculate the Eqalibium constant (K)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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6. Consider the following galvanic cell: Ag- shown: 1.00 M Ag 1.00 M Cd2+ A 15.0-mole sample of NH3 is added to the Ag compartment (assume 1.00 L of total solution after the addition). The silver ion reacts with ammonia to form complex ions as Ag+ (aq) + NH3(aq) AgNH3+ (aq) K₁ 2.1 x 10³ = AgNH3+ (aq) + NH3(aq) ⇒ Ag(NH3)2+(aq) K₂ = 8.2 x 10³ Calculate the cell potential after the addition of 15.0 moles of NH3.
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For the cell diagram below, what is the equilibrium constant K for the reaction at 25 °C? * Pt(s) | [Fe(bpy),2*(aq), [Fe(bpy),]3"(aq) || S,0, (aq), So,2 (aq) | Pt(s) E° ([Fe(bpy),]3*/[Fe(bpy);]*) = +1.12 V E° (S,0, /SO,2) = +2.01 V O 8.54 x 1018 O 8.93 x 107 O 1.22 x 1030 O insufficient data
Consider an electrochemical cell with the following cell notation: Fe(s)| Fe²+ (aq) (from saturated FeCO3) || Fe²+ (aq) (0.150 M) | Fe(s) Given: Ksp of FeCO3 is 3.5 x 10-11 Eºred Fe²+/Fe = -0.44V Which of the following is the expected oxidation half-reaction based on the given cell notation? O FeCO3(s) Fe²+ (aq) + CO3²- (aq) O Fe²+ (aq) + CO3²- (aq) =1 FeCO3(s) O Fe2+ *(aq) + 2 e¯ = Fe(s) O Fe(s) Fe²+ *(aq) + 2 e-
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Calculate the equilibrium constant, K, for the following reaction at 25˚C. 2 Fe3+(aq) + Cu(s) → 2 Fe2+(aq) + Cu2+(aq) E° = 0.46 V Give your answer in scientific notation (e.g. 211 is 2.11e2)
156. Subject :- Chemistry
Give detailed Solution with explanation needed
Use cell potential to calculate the standard free energy change for this reaction. MnO4- (aq) + 8 H+ (aq) + 5 Fe2+ (aq) --> MN2+ (aq) + 4 H2O (l) +5 Fe3+ (s) a. -357 kJ b. 357 kJ c. 941 kJ d. -941 kJ e. 1130 kJ
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