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can someone help me understand what does those two haskell function do myFun1::[a] -> (b -> a -> b) -> b -> [b] myFun1 [] f b = [b] myFun1 (x:xs) f b = (b):myFun3 xs f (f b x)   myFun2::[a] -> [b] -> (a -> c) -> (b -> c) -> [(c,c)] myFun2 [] _ f g = [] myFun2 _ [] f g = [] myFun2 (x:xs) (y:ys) f g = (f x, g y):myFun2 xs ys f g

can someone help me understand what does those two haskell function do myFun1::[a] -> (b -> a -> b) -> b -> [b] myFun1 [] f b = [b] myFun1 (x:xs) f b = (b):myFun3 xs f (f b x)   myFun2::[a] -> [b] -> (a -> c) -> (b -> c) -> [(c,c)] myFun2 [] _ f g = [] myFun2 _ [] f g = [] myFun2 (x:xs) (y:ys) f g = (f x, g y):myFun2 xs ys f g

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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can someone help me understand what does those two haskell function do

myFun1::[a] -> (b -> a -> b) -> b -> [b]

myFun1 [] f b = [b]

myFun1 (x:xs) f b = (b):myFun3 xs f (f b x)

 

myFun2::[a] -> [b] -> (a -> c) -> (b -> c) -> [(c,c)]

myFun2 [] _ f g = []

myFun2 _ [] f g = []

myFun2 (x:xs) (y:ys) f g = (f x, g y):myFun2 xs ys f g

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