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Remember the "init" function of Haskell? It can be defined in Haskell as: init:: [a] -> [a] init [_] = [] init (x:xs) = x : init xs Formulate the appropriate Prolog rule "init(Xs,Ys)" which is true if (and only if) "Ys" is the initial part of "Xs". That is, the query "init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or the query "init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]". Hint: this rule will be recursive, and will have a corresponding base case and recursive case, each analogous to the base case and recursive case, respectively, of the above Haskell function the main ‒‒‒ difference being that the Prolog rule "init(Xs,Ys)" is a predicate, not a function.

Remember the "init" function of Haskell? It can be defined in Haskell as: init:: [a] -> [a] init [_] = [] init (x:xs) = x : init xs Formulate the appropriate Prolog rule "init(Xs,Ys)" which is true if (and only if) "Ys" is the initial part of "Xs". That is, the query "init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or the query "init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]". Hint: this rule will be recursive, and will have a corresponding base case and recursive case, each analogous to the base case and recursive case, respectively, of the above Haskell function the main ‒‒‒ difference being that the Prolog rule "init(Xs,Ys)" is a predicate, not a function.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Prolog
Remember the "init" function of Haskell? It can be defined in Haskell as: init:: [a] -> [a] init [_] = [] init (x:xs) = x : init xs Formulate the appropriate Prolog rule "init(Xs,Ys)" which is true if (and only if) "Ys" is the initial part of "Xs". That is, the query "init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or the query "init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]". Hint: this rule will be recursive, and will have a corresponding base case and recursive case, each analogous to the base case and recursive case, respectively, of the above Haskell function --- the main difference being that the Prolog rule "init(Xs,Ys)" is a predicate, not a function.
Transcribed Image Text:Remember the "init" function of Haskell? It can be defined in Haskell as: init:: [a] -> [a] init [_] = [] init (x:xs) = x : init xs Formulate the appropriate Prolog rule "init(Xs,Ys)" which is true if (and only if) "Ys" is the initial part of "Xs". That is, the query "init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or the query "init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]". Hint: this rule will be recursive, and will have a corresponding base case and recursive case, each analogous to the base case and recursive case, respectively, of the above Haskell function --- the main difference being that the Prolog rule "init(Xs,Ys)" is a predicate, not a function.
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