Remember the "init" function of Haskell? It can be defined in Haskell as: init:: [a] -> [a] init [_] = [] init (x:xs) = x : init xs Formulate the appropriate Prolog rule "init(Xs,Ys)" which is true if (and only if) "Ys" is the initial part of "Xs". That is, the query "init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or the query "init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]". Hint: this rule will be recursive, and will have a corresponding base case and recursive case, each analogous to the base case and recursive case, respectively, of the above Haskell function the main ‒‒‒ difference being that the Prolog rule "init(Xs,Ys)" is a predicate, not a function.
Remember the "init" function of Haskell? It can be defined in Haskell as: init:: [a] -> [a] init [_] = [] init (x:xs) = x : init xs Formulate the appropriate Prolog rule "init(Xs,Ys)" which is true if (and only if) "Ys" is the initial part of "Xs". That is, the query "init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or the query "init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]". Hint: this rule will be recursive, and will have a corresponding base case and recursive case, each analogous to the base case and recursive case, respectively, of the above Haskell function the main ‒‒‒ difference being that the Prolog rule "init(Xs,Ys)" is a predicate, not a function.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Prolog
![Remember the "init" function of Haskell? It can be
defined in Haskell
as:
init:: [a] -> [a]
init [_] = []
init (x:xs) = x : init xs
Formulate the appropriate Prolog rule "init(Xs,Ys)"
which is true if
(and only if) "Ys" is the initial part of "Xs". That is, the
query
"init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or
the query
"init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]".
Hint: this rule will be recursive, and will have a
corresponding base
case and recursive case, each analogous to the base
case and recursive
case, respectively, of the above Haskell function ---
the main
difference being that the Prolog rule "init(Xs,Ys)" is a
predicate,
not a function.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdd1340e1-026e-4b10-9e6b-a53bd1323fd7%2F0c39c563-8ee5-4165-8aa1-c1b5d3cf3af4%2F1ses426_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Remember the "init" function of Haskell? It can be
defined in Haskell
as:
init:: [a] -> [a]
init [_] = []
init (x:xs) = x : init xs
Formulate the appropriate Prolog rule "init(Xs,Ys)"
which is true if
(and only if) "Ys" is the initial part of "Xs". That is, the
query
"init([1,2,3,4,5],[1,2,3,4])." would evaluate to "true", or
the query
"init([1,2,3,4,5],Ys)." would give "Ys = [1,2,3,4]".
Hint: this rule will be recursive, and will have a
corresponding base
case and recursive case, each analogous to the base
case and recursive
case, respectively, of the above Haskell function ---
the main
difference being that the Prolog rule "init(Xs,Ys)" is a
predicate,
not a function.
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