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Calculations Determine the weight of Na,CO, using the formula as: wt.*1000 M Mwt.*V or, wt.*1000 N = Eq.wt.*V Where M, N are the molarity (mol/1) and normality (Eq/1) of primary standard solution, respectively. Wt., Mwt., and Eq.wt. are the weight(gm), molecular weight (106 gm/mol), and equivalent weight(106/2-53 gm/eq) of Na,CO, respectively. V is the volume of the solution prepared (250 ml). Discussion 1- Find the required weight of Na;CO, to prepare 500ml of 2M and 2N standard solution. 2- Why sodium carbonate is primary solution? 3- Why standard solution should be colorless? 4- What is the difference between primary and secondary standard substances?

Calculations Determine the weight of Na,CO, using the formula as: wt.*1000 M Mwt.*V or, wt.*1000 N = Eq.wt.*V Where M, N are the molarity (mol/1) and normality (Eq/1) of primary standard solution, respectively. Wt., Mwt., and Eq.wt. are the weight(gm), molecular weight (106 gm/mol), and equivalent weight(106/2-53 gm/eq) of Na,CO, respectively. V is the volume of the solution prepared (250 ml). Discussion 1- Find the required weight of Na;CO, to prepare 500ml of 2M and 2N standard solution. 2- Why sodium carbonate is primary solution? 3- Why standard solution should be colorless? 4- What is the difference between primary and secondary standard substances?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Calculations Determine the weight of NazCO3 using the formula as: wt. *1000 M = or, Mwt.*V wt.*1000 N = Eq.wt.*V Where M, N are the molarity (mol/l) and normality (Eq/l) of primary standard solution, respectively. Wt., Mwt., and Eq.wt. are the weight(gm), molecular weight (106 gm/mol), and equivalent weight(106/2%353 gm/eq) of Na,CO3, respectively. V is the volume of the solution prepared (250 ml). Discussion 1- Find the required weight of Na,CO, to prepare 500ml of 2M and 2N standard solution. 2- Why sodium carbonate is primary solution? 3- Why standard solution should be colorless? 4- What is the difference between primary and secondary standard substances?
Transcribed Image Text:Calculations Determine the weight of NazCO3 using the formula as: wt. *1000 M = or, Mwt.*V wt.*1000 N = Eq.wt.*V Where M, N are the molarity (mol/l) and normality (Eq/l) of primary standard solution, respectively. Wt., Mwt., and Eq.wt. are the weight(gm), molecular weight (106 gm/mol), and equivalent weight(106/2%353 gm/eq) of Na,CO3, respectively. V is the volume of the solution prepared (250 ml). Discussion 1- Find the required weight of Na,CO, to prepare 500ml of 2M and 2N standard solution. 2- Why sodium carbonate is primary solution? 3- Why standard solution should be colorless? 4- What is the difference between primary and secondary standard substances?
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