[Step-2] mass of fheno fhonol of %3D mole Molaro mass of fhonol [Holam 94.11 gm/mol mass of Pheorol mass of watero 2. Mole of watero = Molar mass of watya [Molove = 18 gm/mol ] mass of watere mole of fheorol mole of watert mole 'oB hendl 3 Prenol mole fraction = 4 % Prorol mole of Rue move of vatap +mole of water X100 of water and mass of Phenol giver 7 watere Now, mass are Phonol % of T'c Phooo mol mass mol frnaction mass mol 4 14 =0.22 0.325 18 35 10 32.5 28.) 46 =0•27'0•281 /8 =0:33 0.24 3 /13=0.44 0.194 0.138 10 0.106 18 10 O•106 24.3 50 10 0.106 19.4 58 10 T0 0.106 12 0.66 13.8 6 3 0.106 15 0.83 0.113. I1.3 65 15 15/4.1|=0:16 25 1.38 10,3 63 6.103 15 O46 28 1,55 0.093 9. 3 64 15 O.16 35 ,の4|| 0.0 76 7.6 57 46 そら 17.5 = 0-185 50 2.77 0.062 6.2 04.11 175 0,185. ら5 3.05 0.057 5.7 33
[Step-2] mass of fheno fhonol of %3D mole Molaro mass of fhonol [Holam 94.11 gm/mol mass of Pheorol mass of watero 2. Mole of watero = Molar mass of watya [Molove = 18 gm/mol ] mass of watere mole of fheorol mole of watert mole 'oB hendl 3 Prenol mole fraction = 4 % Prorol mole of Rue move of vatap +mole of water X100 of water and mass of Phenol giver 7 watere Now, mass are Phonol % of T'c Phooo mol mass mol frnaction mass mol 4 14 =0.22 0.325 18 35 10 32.5 28.) 46 =0•27'0•281 /8 =0:33 0.24 3 /13=0.44 0.194 0.138 10 0.106 18 10 O•106 24.3 50 10 0.106 19.4 58 10 T0 0.106 12 0.66 13.8 6 3 0.106 15 0.83 0.113. I1.3 65 15 15/4.1|=0:16 25 1.38 10,3 63 6.103 15 O46 28 1,55 0.093 9. 3 64 15 O.16 35 ,の4|| 0.0 76 7.6 57 46 そら 17.5 = 0-185 50 2.77 0.062 6.2 04.11 175 0,185. ら5 3.05 0.057 5.7 33
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
drawing the following ;
Plot the numerical values given in the table according to the graphic example below.
Transcribed Image Text:66
% Fenol
100
Fenol - Su Diyagramı
![[Step-→2]
mass of fhemol
of
fhonol
ニ
mole
Molaro
mass of fhonol
Holar mass of fherol = 94.11 gm/mol]
Molare
mass of watero
Molo of watero =
Molar mass of watga
Molone mass of water = 18 gm/mol
mole of fheono
Prenol mole fraction
3
mole of water + mole 'ob thendd
4
mole of Au
X100
move of watop +mole of Nater,
Now,
mass
of water and mass of Phenol
are giver
T'c
% of
fhonol
fhenol
watero
mass
Phooro
mol
mol
moi
frraction
mass
4
4=0.22 0.325
18
35
10
32.5
0.106
=0•270.281
28.1
46
10
18
10
O•106
6
/8 =0.33 0.24 3
24.3
50
/3=0.-44 0.194
0.138
0.83 0.113.
10
1の,4
58
6 3
0.106
10
0. 106
12
O.66
13.8
10
0.106
15
11.3
65
15 5/94.1=0-16
1.38
25
6.103
10,3
63
15
O46
28
1,55 0,093
の.3
64
15
1,94 0.076
0.16
7,6
57
46
35
17.5
17.5
の41
2.77 0.0626.2
= 0.185
50
17.5
O,185.
ら5
3.05 0.057
5.7
33](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27e58e72-00cb-4d8e-baff-684310cf8a5f%2F3d207f4a-b8fd-40f6-a5f4-20dbb4c476fc%2Fj73ze26_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[Step-→2]
mass of fhemol
of
fhonol
ニ
mole
Molaro
mass of fhonol
Holar mass of fherol = 94.11 gm/mol]
Molare
mass of watero
Molo of watero =
Molar mass of watga
Molone mass of water = 18 gm/mol
mole of fheono
Prenol mole fraction
3
mole of water + mole 'ob thendd
4
mole of Au
X100
move of watop +mole of Nater,
Now,
mass
of water and mass of Phenol
are giver
T'c
% of
fhonol
fhenol
watero
mass
Phooro
mol
mol
moi
frraction
mass
4
4=0.22 0.325
18
35
10
32.5
0.106
=0•270.281
28.1
46
10
18
10
O•106
6
/8 =0.33 0.24 3
24.3
50
/3=0.-44 0.194
0.138
0.83 0.113.
10
1の,4
58
6 3
0.106
10
0. 106
12
O.66
13.8
10
0.106
15
11.3
65
15 5/94.1=0-16
1.38
25
6.103
10,3
63
15
O46
28
1,55 0,093
の.3
64
15
1,94 0.076
0.16
7,6
57
46
35
17.5
17.5
の41
2.77 0.0626.2
= 0.185
50
17.5
O,185.
ら5
3.05 0.057
5.7
33
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