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Calculate the change in entropy involved in heating 2 moles of CHCI3(g) from a volume of 100 liters at 500K to a volume of 70 liters at 700K. Cp = 7.05 + 35.6 x 10^-3 (T) - 216.9 x 10^ -7 (T^2) cal/mol-K. Select the correct response: O 23.7 cal/K O 12.5 cal/K O 9.85 cal/K O 16.06 cal/K

Calculate the change in entropy involved in heating 2 moles of CHCI3(g) from a volume of 100 liters at 500K to a volume of 70 liters at 700K. Cp = 7.05 + 35.6 x 10^-3 (T) - 216.9 x 10^ -7 (T^2) cal/mol-K. Select the correct response: O 23.7 cal/K O 12.5 cal/K O 9.85 cal/K O 16.06 cal/K

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Calculate the change in entropy involved in heating 2 moles of CHCI3(g) from a volume of 100 liters at 500K to a volume of 70 liters at 700K. Cp = 7.05 + 35.6 x 10^-3 (T) - 216.9 x 10^ -7 (T^2) cal/mol-K. Select the correct response: 23.7 cal/K 12.5 cal/K 9.85 cal/K 16.06 cal/K
Transcribed Image Text:Calculate the change in entropy involved in heating 2 moles of CHCI3(g) from a volume of 100 liters at 500K to a volume of 70 liters at 700K. Cp = 7.05 + 35.6 x 10^-3 (T) - 216.9 x 10^ -7 (T^2) cal/mol-K. Select the correct response: 23.7 cal/K 12.5 cal/K 9.85 cal/K 16.06 cal/K
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