Calculating the mass of an electrolysis product from the applied current In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al2O3) dissolved in molten cryolite (Naz AlF 6), resulting in the reduction of the Al2O3 to pure aluminum. Suppose a current of 3900. A is passed through a Hall-Heroult cell for 28.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. ☐ x10 μ ☑

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter17: Electrochemistry
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Calculating the mass of an electrolysis product from the applied current
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al2O3) dissolved in molten cryolite (Naz AlF 6), resulting in
the reduction of the Al2O3 to pure aluminum.
Suppose a current of 3900. A is passed through a Hall-Heroult cell for 28.0 seconds. Calculate the mass of pure aluminum produced.
Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
☐ x10
μ
☑
Transcribed Image Text:Calculating the mass of an electrolysis product from the applied current In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al2O3) dissolved in molten cryolite (Naz AlF 6), resulting in the reduction of the Al2O3 to pure aluminum. Suppose a current of 3900. A is passed through a Hall-Heroult cell for 28.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. ☐ x10 μ ☑
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