Calculate the theoretical density of NiO, given that it has the rock salt crystal structure. You may want to use the table below. Theatomic weights for Ni and O are 58.69 g/mol and 16.00 g/mol, respectively.Ionic Radius (nm)P =iCationFe²+Ni²+Mg2+Mn2+g/cm³0.0770.0690.0720.067Anion0²-S²-Ionic Radius (nm)0.1400.184

Introduction In this problem, we will use the Avogadro number and molecular weight of NiO to compute its theoretical density. The concentration of mass per unit volume is known as density. We must utilize the molecular weight of NiO and the volume per unit cell for this. Given data: the atomic weight of NiWNi=58.69 g/molthe atomic weigjt the oxygenWO=16.00 g/molionic radius of O2-r2=0.140 nmionic radius of Ni2+r1=0.069 nm Find out: The theoretical density of NiO ρCalculation of the theoretical density of the NiO (ρ) For the calculation of the theoretical density of the following expression will be used, ρ=n(W)N+WoVc×NAρ=density of NiO(W)N=58.69 g/molWo=16.00 g/molVc=volume per unit cellVc=a3a=2Ni2+r1+O2-r2Ni2+r1=0.069 nmO2-r2=0.140 nma=20.069+0.140nma=0.418 nmVc=a3Vc=0.4183 nm3Vc=0.073 nm3/unit cellVc=7.30×10-23 cm3/unit cellNA=Avogadro numberNA=6.022×1023/per unitρ=n(W)N+WoVc×NAρ=458.69+16.007.30×10-23×6.022×1023(ρ)=6.796 g/cm3 Hence the theoretical density of NiO is 6.796 g/cm3.Result: For the given mixture the theoretical density of the NiO (ρ)=6.796 g/cm3