Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH₂) with 0.180 M HCl. The K of methylamine is 5.0 × 10-4. pH =
Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH₂) with 0.180 M HCl. The K of methylamine is 5.0 × 10-4. pH =
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 55P
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Question
11.
![Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH₂) with 0.180 M HCl. The K₂ of
methylamine is 5.0 × 10-4.
pH:
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e0f9961-5d5b-4fb9-9a8a-126373bac13d%2Ffa6c48fe-cb6f-4ea2-b890-1d298944f280%2Fy8v78i_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH₂) with 0.180 M HCl. The K₂ of
methylamine is 5.0 × 10-4.
pH:
=
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