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Calculate the maximum run time for your voltaic cell if it runs at 0.5 A and your initial concentration of CuCl2(aq)CuCl2(aq) was 0.236 M .

Calculate the maximum run time for your voltaic cell if it runs at 0.5 A and your initial concentration of CuCl2(aq)CuCl2(aq) was 0.236 M .

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.144QP
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Given the nature of how a cell is constructed, you would usually deplete the ions at the cathode before completely oxidizing the anode (since the latter would break the circuit). This is because the complete oxidation of the anode would likely only occur if you were using an extremely thin wire of the metal. In this case, let us assume you constructed the voltaic cell using sufficiently sized rods for each metal. This means that the total time you can run your cell will depend on the initial copper ion concentration.

 

Calculate the maximum run time for your voltaic cell if it runs at 0.5 A and your initial concentration of CuCl2(aq)CuCl2(aq) was 0.236 M .

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