Calculate the mass of acetic acid in 100ml of both samples in vinegar. given: NaOH vs CH3COOH Burette solution is NaOH and the pipette solution is 5.0 mL of Vinegar Titration Initial burette reading Final burette reading Volume of NaOH consumed Average volume of NaOH Approximate 0.0 mL 20.1 mL 20.1 mL 20.3 mL Titration 1 0.0 mL 20.9 mL
Calculate the mass of acetic acid in 100ml of both samples in vinegar.
given:
NaOH vs CH3COOH
Burette solution is NaOH and the pipette solution is 5.0 mL of Vinegar
Titration | Initial burette reading | Final burette reading | Volume of NaOH consumed | Average volume of NaOH |
Approximate | 0.0 mL | 20.1 mL | 20.1 mL | 20.3 mL |
Titration 1 | 0.0 mL | 20.9 mL | 20.9 mL | |
Titration 2 | 0.0 mL | 20.0 mL | 20.0 mL |
To find the average volume
Average volume = 20.1 mL + 20.9 mL + 20.0 mL320.1 mL + 20.9 mL + 20.0 mL3
= 20.3 mL
Concentration of Vinegar = Volume of NaOH * Concentration of NaOHVolume of vinegarVolume of NaOH * Concentration of NaOHVolume of vinegar
= 20.3 mL * 0.0647 M5.0 mL20.3 mL * 0.0647 M5.0 mL
= 0.2627 M
Concentration of NaOH = Volume of H2SO4 * Concentration of H2SO4Volume of NaOHVolume of H2SO4 * Concentration of H2SO4Volume of NaOH
= 10.0 mL * 0.205 M31.7 mL10.0 mL * 0.205 M31.7 mL
= 0.0647 M
Estimation of NaOH
NaOH vs H2SO4
Burette solution is NaOH and the pipette solution is 10.0 mL of 0.205 M H2SO4
Titration | Initial burette reading | Final burette reading | Volume of NaOH consumed | Average volume of NaOH |
Approximate | 0.0 mL | 31.8 mL | 31.8 mL | 31.7 mL |
Titration 1 | 0.0 mL | 31.5 mL | 31.5 mL | |
Titration 2 | 0.0 mL | 31.7 mL | 31.7 mL |
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