Question 10 of 13 1. Show complete solution for determining the Molarity of NaOH (use trial 1 only) 2. Calculate the average molarity of NaOH for trial 1 and 2. Answer with text and/or attachments: H E E I I I BI U s x x 工田 Paragraph RobotoLightNew 12pt E - A - A fx 2 1. [1.2075g KHP (1M KHP/204.22g/mol KHP)] / [24.3mL (1L/1000mL)] = 0.243 2. (Trial 1's Mol NAOH + Trial 2's Mol NaOH) / 2 = 0.2425M
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![Question 10 of 13
1. Show complete solution for determining the Molarity of NaOH (use trial 1 only)
2. Calculate the average molarity of NaOH for trial 1 and 2.
Answer with text and/or attachments:
H E E I I I BI U s x x
工田
Paragraph
RobotoLightNew
12pt
E - A - A
fx 2
1. [1.2075g KHP (1M KHP/204.22g/mol KHP)] / [24.3mL (1L/1000mL)] = 0.243
2. (Trial 1's Mol NAOH + Trial 2's Mol NaOH) / 2 = 0.2425M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c767427-9515-42fa-900d-2ab1ac173bae%2F7ee6c91c-7ae1-4d87-b682-ed5f07eeca6b%2F7eudqlw_processed.png&w=3840&q=75)
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