Q1.Calculate the molarity of CH3COOH (in mol dm-3) in the sample vinegar Q2.Calculate the concentration of CH3COOH (in g dm-3) in the sample vinegar Q3. Write the equation of the neutralization reaction in this experiment
Determine the Concentration of Ethanoic Acid in Vinegar
Equipment / Apparatus:
250-mL conical flasks
Clamp
Burette
Graduated cylinder
Pipette
Reagents / Materials:
Vinegar
Phenolphthalein indicator
0.2 M NaOH (standardized)
Calculation: Molarity (M) of ethanoic acid
The average measured volume of the NaOH from titration:
Average volume of NaOH used = (21.5ml + 21.5ml + 21.6ml) / 3 =21.5ml
No of mole of NaOH = Concentration of NaOH (0.2M) × Average volume of NaOH used
When an acid is completely neutralized: No of moles of CH3COOH = No of moles of NaOH
Using the moles of CH3COOH, the molarity of ethanoic acid in the 5.0-mL sample of vinegar is calculated:
Molarity (M) CH3COOH = moles CH3COOH / volume of vinegar (0.005 dm3).
Calculation: Mass / Volume Percent (m/v) of ethanoic acid
To calculate the percent (m/v) of CH3COOH in vinegar, we convert the moles of ethanoic acid to grams using the molar mass of ethanoic acid, 60.1 g/mole.
Mass of CH3COOH = no of moles of CH3COOH × 60.1
Mass / volume percent (m/v) = mass of CH3COOH / volume of vinegar (0.005 dm3)
(Above is sources)
Q1.Calculate the molarity of CH3COOH (in mol dm-3) in the sample vinegar
Q2.Calculate the concentration of CH3COOH (in g dm-3) in the sample vinegar
Q3. Write the equation of the neutralization reaction in this experiment
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