Calculate the lattice formation enthalpy (lattice energy) of TICI(s), in kJ/mol, using the following thermodynamic data: Heat of sublimation 161 kJ/mol for TI lonization energy for 569 kJ/mol TI CI-CI bond energy 223 kJ/mol Electron affinity -369 kJ/mol for CI Heat of formation for -224 kJ/mol TICI kJ/mol 1 2 3. 4 5 6. C 7 8 9 +/- x 100 Tap here or pull up for additional resources LO

Calculate the lattice formation enthalpy (lattice energy) of TICI(s), in kJ/mol, using the following thermodynamic data: Heat of sublimation 161 kJ/mol for TI lonization energy for 569 kJ/mol TI CI-CI bond energy 223 kJ/mol Electron affinity -369 kJ/mol for CI Heat of formation for -224 kJ/mol TICI kJ/mol 1 2 3. 4 5 6. C 7 8 9 +/- x 100 Tap here or pull up for additional resources LO

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

The energy for the following reaction was measured to be -653.0 kJ/mol. K(g) + Cl(g) → KCl(s). Using this fact and data in the table below, calculate the enthalpy (in kJ/mol) required to separate the ions from the lattice for this reaction: KCl(s) → K⁺(g) + Cl⁻(g).
This thermodynamic cycle describes the formation of an ionic compound MX from a metal element M and nonmetal element X in their standard states. Based of the table (picture): A. What is the lattice enthalpy of MX2? (in kJ/mol) B. What is the enthalpy of formation of MX2? (in kJ/mol) C. Suppose the electron affinity of X were bigger and the heat of sublimation of M were smaller. Would MX2 be more or less stable? Or would it be impossible to tell without more information?
Which of the following ions is least likely to form colorful compounds? Sc3+ Mn2+ Fe3+ Co2+ Cr5+
The lattice energy of CaO(s) is -3,460 kilojoules per mole; the lattice energy for K2O is -2,240 kilojoules per mole. Account for this difference.
Place the following elements in... increasing electronegativity: Se Cl S increasing ionization energy: Al P Sr increasing affinity for electrons: K Ge Cl increasing lattice energy: Na2S KCl MgS
Identify the most polar bond in each molecule. (To answer this question you may consult the table of electronegativity values in the table below.) 1A 2A Li Be 1.0 1.5 Na Mg 0.9 1.2 3B 4B 5B 6B 7B 2: CHBRCIF K Ca Sc Ti V Cr Mn Fe 0.8 1.0 1.3 1.5 1.6 1.6 1.5 1.8 Rb Sr Y 0.8 1.0 1.2 1: (CH3)3CCI Zr Nb Mo 1.4 1.6 1.8 <1.0 1.0-1.4 H 2.1 1.5-1.9 2.0-2.4 8B Co 1.8 1B 2B Ni Cu Zn 1.8 1.9 1.6 3A B 2.0 2.5-2.9 3.0-4.0 Al 1.5 Ga 1.6 Te Ru Rh Pd Ag Cd In 1.9 2.2 2.2 2.2 1.9 1.7 1.7 4A 5A 6A 7A с 0 2.5 3.0 3.5 F 4.0 Si 1.8 2.1 P S 2.5 Ge As Se 1.8 2.0 2.4 Sn 1.8 Sb Te 1.9 2.1 At Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po 0.7 0.9 1.1 1.3 1.5 1.7 1.9 2.2 2.2 2.2 2.4 1.9 1.8 1.8 1.9 2.0 2.2 CI 3.0 Br 2.8 I 2.5 Write the symbols for the two atoms involved in the bond, separated by a hyphen, i.e. O-H (note that the answer is case-sensitive).
9. Use the following data to calculate the lattice energy of Cao. The enthalpy of formation of Cao is –636 kj/mol. The enthalpy of sublimation of Ca is +192 kj/mol, the first ionization energy of Ca is +590 kj/mol, and the second ionization energy of Ca is +1145 kj/mol. The enthalpy of dissociation of 02 is +494 kj/mol of 02 molecules, the first electron affinity of O is -141 kj/mol of 0 atoms, and the second electron affinity of 0 is +845 kj/mol of 0¯ ions.
Calculate the lattice energy of RbH (s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. AHsublimation 61 kJ/mol Ionization energy = 383 kJ/mol Rb (s) Rb (g) H - H (g) Bond energy = 416 kJ/mol H (g) Electron affinity = -93 kJ/mol RbH (s) AHOf = -72 kJ/mol kJ/mol
Given the following information, use the Kapustinskii equation (shown below and included in the additional information sheet I encouraged you to download and have available) to calculate the lattice energy for Cr2S3 in kJ/mol. Ionic radii: Cr3+ (62 pm), S2− (184 pm) d* = 34.5 pm Κ = 1.21 × 105 kJ pm/mol
For Na (s) + 1/2 Cl2 (g) ---> NaCl (s) ΔH = -410 kJ, ΔH is the ionization energy endothermic energy heat of formation bond energy lattice energy
Calculate the lattice energy of TIF (s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea. TI (S) TI (g) F - F (g) F (g) TIF (s) AHsublimation = 161 kJ/mol Ionization energy = 569 kJ/mol Bond energy = 138 kJ/mol Electron affinity = -348 kJ/mol AH°f = -345 kJ/mol kJ/mol
Since Na and Cs are both Group 1 metals we might expect the crystal structure of CsCl to be identical to the NaCl. Suggest a reason for the difference between the two crystal structures.