Calculate the fraction of pure ethane that would dehydrogenate at 750 K and 5 atmospheres, if the following reaction goes to equilibrium.C₂H6 (g) → C₂H4 (g) H₂ (g); DGº for the reaction at 750 K = 42.576 kJ. Assume ideal gas behaviour. +

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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Calculate the fraction of pure ethane that would dehydrogenate at 750 K and 5
atmospheres, if the following reaction goes to equilibrium.C₂H6 (g) → C₂H4 (g) +
H₂ (g); DGº for the reaction at 750 K = 42.576 kJ. Assume ideal gas behaviour.
Transcribed Image Text:Calculate the fraction of pure ethane that would dehydrogenate at 750 K and 5 atmospheres, if the following reaction goes to equilibrium.C₂H6 (g) → C₂H4 (g) + H₂ (g); DGº for the reaction at 750 K = 42.576 kJ. Assume ideal gas behaviour.
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