Calculate the factored load capacity of a double channel section member of A36 steel according to AISC LRFD Specification. The member is 4m long and consists of 2Cs 180x18.2, with flanges turned out with clear gap of 90mm. Assume that there can be as many as two 14mm rivets at any one cross-section (one in each flange). U = 0.80. Ag= 2x2320= 4640mm2 U=0.80 L= 4m Clear gap= 90mm Tf= 9.3 Bf= 55 Tw=8.0

Calculate the factored load capacity of a double channel section member of A36 steel according to AISC LRFD Specification. The member is 4m long and consists of 2Cs 180x18.2, with flanges turned out with clear gap of 90mm. Assume that there can be as many as two 14mm rivets at any one cross-section (one in each flange). U = 0.80. Ag= 2x2320= 4640mm2 U=0.80 L= 4m Clear gap= 90mm Tf= 9.3 Bf= 55 Tw=8.0

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.8.3P

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Question

Ag= 2x2320= 4640mm2

U=0.80

L= 4m

Clear gap= 90mm

Tf= 9.3

Bf= 55

Tw=8.0

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