Calculate the Esystem values after the addition of 45.00 mL of 0,0500 M HCIO3 to 25,00 m of 0,0400 M NaAuCl₂: +60H (aq) 3C1O4 (aq) Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titration 3C1O3(aq) + 2AuC14 (aq) Half - Reaction Au³+ +3e (aq) AuCl(aq) + 3e + H₂O C1O4 (aq) Cu²+ + 2e All(s) Aus) + 4C1*(aq) +2e=CIO3(aq) Cu(s) + 2Au(s) + 3H₂O(1) + 8CF (aq) + 20H* Eº +1,68 V +1.00 V +1,19 V +0,340 V

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.54QE
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Calculate the Esystem values after the addition of 45.00 mL of 0,0500 M HCIO3 to 25,00 m
of 0,0400 M NaAuCl₂:
+60H (aq)-
3CIO4 (aq)
Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titration
3CIO3(aq) +2AuC14 (aq)
Half - Reaction
3+
+ 3e=
(aq)
AuCl(aq) + 3e=
+ H₂O
Au
CIO4 (aq)
Cu²+2e=
Y
Au(s)
4C1 (aq)
Au(s)
+2eClO 3 (aq)
Cu(s)
+4C17
+ 2Au(s) + 3H₂O)
3H₂O + 8C1 (aq)
+
2OH-
Eº
+1,68 V
+1.00 V
+1.19 V
+0.340 V
Transcribed Image Text:Calculate the Esystem values after the addition of 45.00 mL of 0,0500 M HCIO3 to 25,00 m of 0,0400 M NaAuCl₂: +60H (aq)- 3CIO4 (aq) Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titration 3CIO3(aq) +2AuC14 (aq) Half - Reaction 3+ + 3e= (aq) AuCl(aq) + 3e= + H₂O Au CIO4 (aq) Cu²+2e= Y Au(s) 4C1 (aq) Au(s) +2eClO 3 (aq) Cu(s) +4C17 + 2Au(s) + 3H₂O) 3H₂O + 8C1 (aq) + 2OH- Eº +1,68 V +1.00 V +1.19 V +0.340 V
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