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Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'eq = 4.74 x10-3 [G6P] = In the rat hepatocyte, the physiological concentrations of glucose and P, are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P,? M-1 1.09 x107 M

Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'eq = 4.74 x10-3 [G6P] = In the rat hepatocyte, the physiological concentrations of glucose and P, are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P,? M-1 1.09 x107 M

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Answer the last question please. 

Does this reaction represent a reasonable metabolic step for the catabolism of glucose? Why or why not? No, because [G6P] is likely to be higher than the calculated value. Yes, because AG' is negative at the calculated value of K'eq Yes, because the value of AG" is positive. No, because the K'eq is too large for the reaction to proceed in the forward direction.
Transcribed Image Text:Does this reaction represent a reasonable metabolic step for the catabolism of glucose? Why or why not? No, because [G6P] is likely to be higher than the calculated value. Yes, because AG' is negative at the calculated value of K'eq Yes, because the value of AG" is positive. No, because the K'eq is too large for the reaction to proceed in the forward direction.
The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P, is described by the equation Glucose + P→→ glucose 6-phosphate + H₂O AG 13.8 kJ/mol Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'ca = [G6P] = 4.74 x10-3 In the rat hepatocyte, the physiological concentrations of glucose and P, are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P,? = M-1 1.09 X10-7 M
Transcribed Image Text:The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by P, is described by the equation Glucose + P→→ glucose 6-phosphate + H₂O AG 13.8 kJ/mol Calculate the equilibrium constant for the phosphorylation of glucose to glucose 6-phosphate at 37.0 °C. K'ca = [G6P] = 4.74 x10-3 In the rat hepatocyte, the physiological concentrations of glucose and P, are maintained at approximately 4.8 mM. What is the equilibrium concentration of glucose 6-phosphate (G6P) obtained by the direct phosphorylation of glucose by P,? = M-1 1.09 X10-7 M
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