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Calculate the equilibrium constant for the following reaction at room temperature, 25 ∘C∘C: CaCO3(s)→CaO(s)+CO2(g)CaCO3(s)→CaO(s)+CO2(g) Express your answer numerically to three significant figures.

Calculate the equilibrium constant for the following reaction at room temperature, 25 ∘C∘C: CaCO3(s)→CaO(s)+CO2(g)CaCO3(s)→CaO(s)+CO2(g) Express your answer numerically to three significant figures.

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Calculate the equilibrium constant for the following reaction at room temperature, 25 ∘C∘C:

CaCO3(s)→CaO(s)+CO2(g)CaCO3(s)→CaO(s)+CO2(g)

Express your answer numerically to three significant figures.
+ Gibbs Free Energy: Equilibrium Constant 10 of 17 I Review | Constants | Periodic Table Calcium oxide, CaO, is manufactured by decomposition of calcium carbonate, CaCO3. in a furnace at 500 K: Submit CaCO3 (s)Ca0(s) + CO2(g) The spontaneity of a reaction can be determined from Relationship between free energy and the equilibrium constant the free energy change for the reaction, AG The standard free energy change, AG". and the equilibrium constant K for a reaction can be related by the following equation: • A reaction is spontaneous when the free AG RT In K energy change is less than zero. A reaction is nonspontaneous when the free energy change is greater than zero. • A reaction is in equilibrium when the free where T is the Kelvin temperature and R is equal to 8.314 J/(mol - K). energy change is equal to zero. Part B The thermodynamic values from part A will be useful as you work through part B: | ΔΗ ASan 161.0J/(mol - K) 178.5kJ/mol Calculate the equilibrium constant for the following reaction at room temperature, 25 °C: CaCO; (s)Cao(s) + CO2 (8) Express your answer numerically to three significant figures. > View Available Hint(s) Πναι ΑΣφ K = Submit
Transcribed Image Text:+ Gibbs Free Energy: Equilibrium Constant 10 of 17 I Review | Constants | Periodic Table Calcium oxide, CaO, is manufactured by decomposition of calcium carbonate, CaCO3. in a furnace at 500 K: Submit CaCO3 (s)Ca0(s) + CO2(g) The spontaneity of a reaction can be determined from Relationship between free energy and the equilibrium constant the free energy change for the reaction, AG The standard free energy change, AG". and the equilibrium constant K for a reaction can be related by the following equation: • A reaction is spontaneous when the free AG RT In K energy change is less than zero. A reaction is nonspontaneous when the free energy change is greater than zero. • A reaction is in equilibrium when the free where T is the Kelvin temperature and R is equal to 8.314 J/(mol - K). energy change is equal to zero. Part B The thermodynamic values from part A will be useful as you work through part B: | ΔΗ ASan 161.0J/(mol - K) 178.5kJ/mol Calculate the equilibrium constant for the following reaction at room temperature, 25 °C: CaCO; (s)Cao(s) + CO2 (8) Express your answer numerically to three significant figures. > View Available Hint(s) Πναι ΑΣφ K = Submit
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