The steam reforming of methane occurs according to the following chemical equation: CH₄(g) + 2H₂O(g) ⇌ CO₂(g) + 4H₂(g) Use the following equations to solve for the enthalpy change of steam reforming of methane: H₂(g) + ½O₂(g) → H₂O(g) ∆H° = -242 kJ/mol 2H₂(g) + C(s) → CH₄(g) ∆H° = -75 kJ/mol C(s) + O₂(g) → CO₂(g) ∆H° = -394 kJ/mol
The steam reforming of methane occurs according to the following chemical equation: CH₄(g) + 2H₂O(g) ⇌ CO₂(g) + 4H₂(g)
Use the following equations to solve for the enthalpy change of steam reforming of methane: H₂(g) + ½O₂(g) → H₂O(g) ∆H° = -242 kJ/mol 2H₂(g) + C(s) → CH₄(g) ∆H° = -75 kJ/mol C(s) + O₂(g) → CO₂(g) ∆H° = -394 kJ/mol
For determination of enthalpy change of steam reforming of methane, we have to calculate the enthalpy change for Following Reaction -
CH₄(g) + 2H₂O(g) ⇌ CO₂(g) + 4H₂(g)
For this purpose we can use Following chemical Reactions -
(1) H₂(g) + ½O₂(g) → H₂O(g) ∆H°1 = -242 kJ/mol
(2) 2H₂(g) + C(s) → CH₄(g) ∆H°2 = -75 kJ/mol
(3) C(s) + O₂(g) → CO₂(g) ∆H°3 = -394 kJ/mol
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