Calculate the desired empirical probabilities (rounded to 3 significant digits) based on the airline passenger satisfaction data, summarized in the following contingency table Compensated Not Compensated TOTAL Satisfied Not Satisfied TOTAL 72 18 90 8 302 310 80 320 400 a.The probability of selecting 3 customers in a row who were not compensated and were not satisfied.
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- The pass completion percentages of 10 college football quarterbacks for their freshman and sophomore seasons are shown in the table below. At a = 0.10, is there enough evidence to support the claim that the pass completion percentages have changed? Complete parts (a) through (e) below. Player 4 5 6 7 8 9 10 Completion percentage (freshman) 1 2 3 68.3 62.1 56.3 59.0 62.1 51.0 58.0 62.6 54.9 57.1 Completion percentage (sophomore) 67.9 57.1 62.6 59.6 60.8 59.2 63.8 61.6 56.0 58.2 OD. The pass completion percentages have not changed. Let Hd be the hypothesized mean of the differences in the pass completion percentages (freshman - sophomore). Then d is the sample mean of the differences. What are Ho and H₂? O A. Ho: Hd 20 B. Ho: Hd = 0 OC. Ho: Hd #0 Ha: Hd = 0 Ha: Hd 0 Ha: HdNow assume it is true that 60.98% of all words in the English language contain the letter "e" (as given in the source above). Generate a simulated distribution of 1000 sample statistics for simulated samples of 20 words from the English language. In the space below, include a copy-and-paste of your simulated distribution. You need to be using the "Proportion of Successes" option, and that is the picture you need to copy and paste. Your picture needs to show all the values that you entered in the applet. (h) If we used this simulated distribution of sample statistics and the 2SD rule to find the "cutoffs" for "usual" vs." unusual" sample statistics, then what would those cutoff values be? Find the values, and show all your work. (i) Which of the following conclusions does your observed sample statistic support? It is plausible that 60.98% of words in the English language contain the letter "e"? OR We have statistically significant evidence that the percentage of words in…Workers at a private business was given a grade (A, B, C) based on their yearly performance. The data was recorded along with the department they belong. The results obtained using MINITAB are shown below: Expected counts are printed below observed counts A B C Total 12 8 7 Accounting (12.960) (7.830) (6.210) * 17 10 8 Sales (16.800) (10.150) (8.050) 35 19 11 8 Marketing (18.240) (**) (8.740) 38 Total 48 29 23 100 Chi-sq = 0.0711 + 0.0037 + 0.1005 + 0.0024 + 0.0022 + 0.003 + 0.0317 + 0.0000 +…The contingency table below shows the results of a survey of video viewing habits by age. Video Viewing Platform Preferred Viewer Age Mobile/Laptop Device TV Screen Row Total 18–34 40 28 68 35–54 9 9 18 55+ 5 9 14 Column Total 54 46 100 Find the following probabilities or percentages: (d) Percentage of viewers given they are 18–34 who prefer videos on a mobile or laptop device. (Round your answer to 2 decimal places.) Percentage of viewers % (e) Percentage of viewers who are 35–54 or prefer videos on a mobile or laptop device. Percentage of viewers % check_circleAn educational researcher wishes to know if there is a difference in academic performance for college freshmen that live on campus and those that commute. Data was collected from 229 students. Can we conclude that freshman housing location and academic performance are related? Location Average Below Average Above Average Total On campus 92 48 42 182 Off campus 23 11 13 47 Total 115 59 55 229 Copy Data Step 3 of 8: Find the expected value for the number of students that live off campus and have academic performance that is below average. Round your answer to one decimal place. E Tables E Keypad nswer ow to enter your answer Keyboard Shortcuts Previous Step Answers POff campus and below averageYou want to see if it makes a difference which lane to be in when there is traffic. You randomly observe 372 cars as they pass by on the four lane freeway. The results are displayed in the table below. Use a level of significance of a = 0.01. a. Complete the rest of the table by filling in the expected frequencies: of Cars in Each Lane Frequency Outcome Frequency Expected Frequency Lane 1 89 Lane 2 98 Lane 3 92 Lane 4 93 b. What is the correct statistical test to use? Select an answer Y C. What are the null and alternative hypotheses? Ho: OThe distribution of traffic is not uniform. O The traffic and lanes are independent. O The distribution of traffic is uniform. KO The traffic and lanes are dependent. Hi : OThe distribution of traffic is uniform. OThe traffic and lanes are independent. O The traffic and lanes are dependent. O The distribution of traffic is not uniform.